AQA GCSE COMBINED SCIENCE: TRILOGY Foundation Tier Physics Paper 2F QP 2023
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GCSE
COMBINED SCIENCE: TRILOGY
Foundation Tier
F
Physics Paper 2F
Friday 16 June 2023 Morning Time allowed: 1 hour 15 minutes
Materials
For Examiner’s Use
For this paper you must have:
a protractor Question Mark
a ruler
1
a scientific calculator
the Physics Equations Sheet (enclosed). 2
3
Instructions 4
Use black ink or black ball-point pen.
Pencil should only be used for drawing. 5
Fill in the boxes at the top of this page. 6
Answer all questions in the spaces provided. 7
If you need extra space for your answer(s), use the lined pages at the end of
this book. Write the question number against your answer(s). TOTAL
Do all rough work in this book. Cross through any work you do not want to be
marked.
In all calculations, show clearly how you work out your answer.
Information
The maximum mark for this paper is 70.
The marks for questions are shown in brackets.
You are expected to use a calculator where appropriate.
You are reminded of the need for good English and clear presentation in your answers.
IB/M/Jun23/E7
8464/P/2F
, 2
Do not write
outside the
0 1 Figure 1 shows a garden chair hanging from a spring. box
Figure 1
The weight of the person causes the spring to extend.
0 1
. 1 Why does the weight of the person cause the spring to extend?
[1 mark]
Tick () one box.
Weight acts downwards
Weight acts in all directions
Weight acts upwards
IB/M/Jun23/8464/P/2F
, 3
Do not write
outside the
0 1 . 2 Complete the sentence. box
Choose the answer from the box.
[1 mark]
a gravitational a frictional an electrostatic
The weight of the person in Figure 1 is force.
Question 1 continues on the next page
Turn over ►
IB/M/Jun23/8464/P/2F
, 4
Do not write
outside the
The weight of the person causes an extension in the spring of 0.070 m. box
The spring constant of the spring is 12 000 N/m.
0 1 . 3 Calculate the weight of the person.
Use the equation:
weight = spring constant × extension
[2 marks]
Weight = N
0 1 . 4 Calculate the elastic potential energy stored in the extended spring.
Use the equation:
elastic potential energy = 0.5 × spring constant × (extension)2
[2 marks]
Elastic potential energy = J
IB/M/Jun23/8464/P/2F
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