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DAT - Chem Exam 2 Questions with 100% correct answers

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DAT - Chem Exam 2 Questions with 100% correct answers

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  • June 16, 2024
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DAT - Chem Exam 2
A volumetric flask weighs 185g when empty and 380g when filled with "liquid

✅✅
A" (density of 2 g•mL-1). If the flask is filled with 160g of "liquid B", what is the
density of "liquid B" in g•mL-1? - -volume of A = volume of B

380g-185g = 195 g = Vol of A = Vol B

195g x (1 mL/2g) = 100 mL

160 g/100 mL = 8/5


✅✅
What is the sum of the coefficients of the complete balanced equation from
combusting C2H6O? - -1 C2H6O + 3 O2 → 2 CO2 + 3 H2O

combustion: hydrocarbon (CxHy) or alc (CxHyOH) react with O2 to make CO2
and H2O

assumptions of an ideal gas - ✅✅ ->All gas molecules are in constant, rapid,
and random motion.
>There are no attractive or repulsive forces between the gases.
>The volume of the molecules is negligibly small compared to the volume of
the gas.
>All collisions within the gas are perfectly elastic


✅✅
Which statement best explains why bromine is a liquid and iodine is a solid at
STP? - -London dispersion inc as molar mass inc

what are examples of nonpolar - ✅✅-iodine and bromine (I2 and Br2)
✅✅
following statements accurately describe why mercury forms a convex
meniscus in a glass thermometer - -mercury is nonpolar + glass is polar
since "like like like" mercury and glass want to be as far apart as possible

cohesion force > adhesion force

capillary action work for both convex and concave

INCORRECT: mercury tends to be ionized and net charges repel glass

, colligative property - ✅✅
-number of solvent or solute particles in a solution
(anything with molarity or molality)

density is an example of - ✅✅
-intensive property. number of particles not
matter but the identity of the particles

The boiling point of a 1.0m aqueous solution is 101.5°C. The molal boiling

✅✅
point constant for water is 0.512°C•m-1. Which of the following substances is
most likely dissolved in the water? - -ΔT (bp) = iKm

i = number of parts dissolved

Boiling: ΔT = x - 100

ΔT = iKm
101.5-100 = i (0.512)(1)
i=3

Na2SO4

neutralize a solution - ✅✅-nMV = nMV
n = # of H!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


✅✅
What volume of 0.5M H2SO4 is needed to neutralize 250mL of 0.5M KOH? -
-(n1)(M1)(V1) = (n2)(M2)(V2)

(2)(0.5)(V1) = (1)(0.5)(250)

V1 = 125 mL


✅✅
What is the molar solubility of PbSO4 in 4.0 × 10-2 M Pb(NO3)2 solution? The
Ksp for PbSO4 is 1.6 × 10-8 - -Ksp = [Pb2+][SO42-] = (0.04 + x)(x)

1.6 × 10-8 = 0.04x

MY OWN MATH ERROR: (1.6x10^-8)/(4x10^-2)
[= (-8) - (-2) = -6]
(16x10^-9)/(4x10^-2)
=4x10&-7

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