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Ch.5 ASNT Study Guide_ Industrial Radiography Radiation Safety questions and answers
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Ch.5 ASNT Study Guide_ Industrial Radiography Radiation Safety questions and answers
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Ch.5 ASNT Study Guide: IndustrialRadiography Radiation Safety
A specific gamma ray constant can be stated as: - correct answer-a. dose rate per curie at a
specific distance
At a dose rate of 60 mRh/ (600 uSv/h), 1 h of exposure would be? - correct answer-d. 60 mR
(600 uSv)
If the radiographer has 100 mR/h at 25 ft (1000 uSv at 7.63 m), the exposure rate at 50 ft
(15.24 m) would be ____________ with 1 half- value layer of shielding between the
radiographer and the source. - correct answer-b. 12.5 mR per hour
If you have 73 Ci of Co-60, your exposure rate at 2 ft (0.6 m) from the source would be? -
correct answer-d.255.5 R at 2 ft
Mathematically, the inverse is written as: - correct answer-c. I1/I2 = D2^2/ D1^2
Shielding can be expressed by the amount of shilding provided, so that the amount of
shielding that would reduce the original exposure rate to one-half would be stated as: -
correct answer-a. 1 half-value layer
Standing in a 100 mR/h (1000 uSv/h) field , the radiographer will make four 10 min
exposures. The radiographer's total exposure for the day would be: - correct answer-b. 66.7
mR
The best material to use as shielding would be: - correct answer-d. lead
The inverse square law can be broken down to solve for distance as: - correct answer-c.
D2={[I1*D1^2)/I2]
The inverse square law can be broken down to solve for intensity as: - correct answer-a. I2 =
(I1*D1^2)/D2^2
The inverse square law is written as: - correct answer-b. the intensity is indirectly
proportional to the distance squared
The most common type of installation used in the field radiography is: - correct answer-a.
open
The specific gamma ray constant for Co-60 can be expressed as: - correct answer-d. 14
R/Ci at 1 ft (140 mSv/Ci at 1 ft)
The specific gamma ray constant for Ir-192 can be expressed as: - correct answer-d. 5.2
R/h/Ci at 1 ft (52 mSv/h/Ci at 1 ft)
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