Summary
Summary - Unit 3 - Redox I
- Module
- Unit 3 - Redox I
- Institution
- PEARSON (PEARSON)
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REDOX IREDOX -
when reduction and Oxidation happens simultaneously
OXIDATION NUMBER -
hypothetical charge of an atom if all of its bonds to oth
DISPROPORTIONATION -
an element in a single species being simultaneously oxidise
S-block metal-oxidise to form trive ions ↑ oxidation .
no
form-tiveions boxidation .
no
p-block metal-reduce to
#
OXIDISING AnGENT-gains electrons
REDUCING AGENT - loses elections
GROUP 1/2 +
Oxidation Reduction ALUMINIUM
FLOURINE
Is Is
#
Loss of - Gain of e- CHLORINE -
BALANCING HALF-EQUATIONS
BALANCING HALF-EQUATIONS :
ACIDIC SOLUTIONS
e .
. MeOz and
g MnOy- react in al
1) break into half equations
2) balance all other elements except O and
I
3) balance O by adding H20 2420 +
MnO2
+
4) balance H H e
by adding +
MnQ
J
ensure e- are on opposite
5) balance with e-
charges sides of
ISO2-
-
ensure to remember
6) multiplication + 2 Mot
balance e-between equations with to
simplify
7) Write as one equation
24 20 + Mn0z + 2 Mn0
BALANCING HALF-EQUATIONS :
BASIC SOLUTIONS + 4 OH
1) work out the acidic answer
4 Or + 220 + MeOz + 2 MnO
2) add as OH-to both sides A+
many as there is
4 On MnOz 2 Mn
-
+ +
3) cancel out the H20 formed
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