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C960 Discrete Math 2 Exam Questions and Complete Solutions Graded A+
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C960 DiscreteMath 2 Exam
Questions and
Complete Solutions
Graded A+
Denning [Date] [Course title]
,1.4.3: If-else-statement
1)
What is the value of abs after the following lines of code are run?
x := 2
If ( x > 0 )
abs := x
Else abs := -x
End-if - Answer: 2
The condition ( x > 0 ) evaluates to true because the value of x is 2. The line abs := x is executed and the
line abs := -x is skipped. Therefore the final value of abs is 2.
1.4.3: If-else-statement
2)
What is the value of abs after the following lines of code are run?
x := -2
If ( x > 0 )
abs := x
Else
abs := -x
End-if - Answer: 2
The condition ( x > 0 ) evaluates to false because the value of x is -2. The line abs := x is skipped and the
line abs := -x is executed. Therefore the final value of abs is -x, which is -(-2) = 2.
1.5.2: For-loops
Consider the following pseudocode fragment:
sum := 0
,For i = 2 to 5
sum := sum + i
End-for
1) What is the value of sum after the second iteration?
2) How many iterations will the for-loop execute?
3) What is the final value for sum after executing the for-loop? - Answer: 1) 5
In the first iteration, i = 2. In the second iteration, i = 3. 2 + 3 = 5
2) 4
i = 2, 3, 4, 5. Four iterations
3) 14
i = 2, 3, 4, 5. sum = 2 + 3 + 4 + 5
1.6.2: While-loops
product := 1
count := 5
While ( count > 0 )
product := product⋅count
count := count - 2
End-while
1) What is the value of product after the second iteration?
2) How many iterations will the while-loop execute?
, 3) What is the final value for product? - Answer: 1) 15
In the first iteration, count = 5. In the second iteration, count = 3. 5⋅3 = 15
2) 3
count = 5, 3, 1. Three iterations
3) 15
product = 5⋅3⋅1 = 15
1.7.2: Nested loops - example 1
count := 0
For i = 1 to 3
For j = 1 to 4
count := count + i ⋅ j
End-for
End-for
1) How many times is the variable count increased?
2) What is the final value of count? - Answer: 1) 12
For each iteration of the outer loop, the inner loop iterates 4 times. The outer loop iterates 3 times. 3 ×
4 = 12
2) 60
1·(1 + 2 + 3 + 4) + 2(1 + 2 + 3 + 4) + 3(1 + 2 + 3 + 4) = 60
1.7.3: Nested loops - example 2
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