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BIOL 3301 Genetics final exam tips (with prof meisel and dauwalder) actual questions with star marked correct answers University of Houston £10.63   Add to cart

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BIOL 3301 Genetics final exam tips (with prof meisel and dauwalder) actual questions with star marked correct answers University of Houston

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  • BIOL 3301 Genetics

BIOL 3301 Genetics final exam tips (with prof meisel and dauwalder) actual questions with star marked correct answers University of Houston

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  • September 8, 2024
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  • 2024/2025
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  • BIOL 3301 Genetics
  • BIOL 3301 Genetics
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BIOL 3301 Genetics final exam tips (with prof meisel and
dauwalder) actual questions with star marked correct
answers University of Houston

,You count 1000 F2 seeds from a monohybrid cross. How many seeds do you expect to display
the dominant phenotype?

A) 1000
*B) 750
C) 500
D) 250
E) 0

You count 1000 F2 seeds from a monohybrid cross. How many seeds do you expect to display
the recessive phenotype?

A) 1000
B) 750
C) 500
*D) 250
E) 0

In peas, axial (A) flower position is dominant to terminal (a), tall (L) is dominant to short (l), and
yellow (Y) is dominant to green (y). If a plant that is heterozygous for all three traits is allowed
to self-fertilize, how many of the offspring would show the dominant phenotype for all three
traits?

A) 3/64
B) 9/64
*C) 27/64
D) 32/64
E) 64/64

In peas, axial (A) flower position is dominant to terminal (a), tall (L) is dominant to short (l), and
yellow (Y) is dominant to green (y). If a plant that is heterozygous for all three traits is allowed
to self-fertilize, how many of the offspring will be axial, short, and yellow?

*A) 3/64
B) 9/64
C) 27/64
D) 32/64
E) 64/64

,In peas, axial (A) flower position is dominant to terminal (a), tall (L) is dominant to short (l), and
yellow (Y) is dominant to green (y). If a plant that is heterozygous for all three traits is allowed
to self-fertilize, how many of the offspring will be axial, tall, and yellow?

A) 3/64
*B) 9/64
C) 27/64
D) 32/64
E) 64/64

The gene L determines hair length in rabbits. The gene B determines hair color. A rabbit with
long, black hair is crossed to a rabbit with short, white hair. All the offspring have long, black
hair. What are the genotypes of the parents?

*A) LLBB × llbb
B) LlBb × LlBb
C) LlBb × llbb
D) Llbb × llBb
E) Impossible to determine from the information given

The gene L determines hair length in rabbits. The gene B determines hair color. A rabbit with
long, black hair is crossed to a rabbit with short, white hair. Half the offspring have long, black
hair and half have short, white hair. What are the genotypes of the parents?

A) LLBB × llbb
B) LlBb × LlBb
*C) LlBb × llbb
D) Llbb × llBb
E) Impossible to determine from the information given

The gene L determines hair length in rabbits. The gene B determines hair color. A rabbit with
short, black hair is crossed to a rabbit with long, white hair. All the offspring have long, black
hair. What are the genotypes of the parents?

A) LLBB × llbb
*B) llBB × LLbb
C) LlBb × llbb
D) Llbb × llBb
E) Impossible to determine from the information given

, In the accompanying figure, the chance that individual IV-7 is a heterozygous carrier is
________.

A) 1/4
B) 1/3
C) 1/2
*D) 2/3
E) 3/4

In the accompanying figure, the chance that individual IV-7 is NOT a heterozygous carrier is
________.

A) 1/4
*B) 1/3
C) 1/2
D) 2/3
E) 3/4

A geneticist is investigating the inheritance of two autosomal recessive genes in mice, one for
obesity (LEP) and another for autism (oprm1). The table below provides the number of
offspring observed, for each phenotype, when dihybrid mice are crossed:

Phenotype. Observed
wild-type. 154
obese 69
autistic 58
obese, autistic 23

What is the Chi-square value for this cross?

What is the probability that the observed deviation from the expected is caused by chance?

*a) 5.08
b) 0.34
c) 121.9
d) 0.05

*a) larger than 0.5 - conclude that differences are caused by chance
b) larger than 0.5 - conclude that differences are significant and not by chance
c) smaller than the 0.05 cutoff for significance

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