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solution manual An Introduction to Combustion Concepts and Applications Turns Haworth 4th Edition

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Solution Manual An Introduction to Combustion Concepts and Applications Turns Haworth 4th Edition - Updated 2024 Complete Solution Manual With Answers

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  • October 19, 2024
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PROBLEM 2-1

Determine the mass fraction of O2 and N2 in air, assuming the molar composition is 21 percent O2
and 79 percent N2.

GIVEN: Air with a molar composition of 79% N2 and 21% O2

FIND: The mass fraction of O2 and N2 in the air

APPROACH: This is a simple conversion problem using:
MWi
MWmix   i MWi and Yi  i
MWmix
Given the molar composition:  N 2  0.79 and O2  0.29
mixture molecular weight:
MWmix  i MWi   N2 MWN2   O2 MWO2
 0.79  28.013   0.21 32   28.85 kg/kmol
mass fraction of O2 and N2
 MWO2   32 
YO2  O2    0.21   0.233
 MWmix   28.85 
 MWN2   28.013 
YN2   N2    0.79    0.767
 MWmix   28.85 

COMMENT: Note that YO2   O2 since MWO2  MWmix and that  Yi  1 as would be expected.




Copyright 2021 © McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior
written consent of McGraw-Hill Education. 2-30

, PROBLEM 2-2

A mixture is composed of the following number of moles of various species:
Species No. of moles
CO 0.095
CO2 6
H2O 7
N2 34
NO 0.005
A. Determine the mole fraction of nitric oxide (NO) in the mixture. Also, express your result as
mole percent, and as parts-per-million.
B. Determine the molecular weight of the mixture.
C. Determine the mass fraction of each constituent.

GIVEN: The following mixture:

Species # Moles i Yi MWi
CO 0.095 0.002 0.002 28.010
CO2 6 0.127 0.195 44.011
H2 O 7 0.149 0.094 18.016
N2 34 0.722 0.707 28.013
NO 0.005 106  10−6 111  10−6 30.006
TOTAL 47.1 1.0 1.0


FIND:

a) The mole fraction, mole %, and ppm of NO in the mixture
b) Determine the MW of the mixture
c) Determine the mass fraction of each constituent


Ni N NO 0.005
a) i   
 Ni N CO  N CO2  N H2O  N N2  N NO 0.095  6  7  34  0.005

 NO  106 106 kmol/kmol-mix
MOLE %  i 100  0.0106 %
N A
PPM 
# NO
TOT #
1106   NO
 Ni  A
1106    NO 1106   106 ppm

where A ≡ Avogadro’s Number

b) MWmix   i MWi  CO MWCO  CO2 MWCO2   H 2O MWH 2O   N 2 MWN 2   NO MWNO

Copyright 2021 © McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior
written consent of McGraw-Hill Education. 2-31

, where CO , CO2 ,  H2O , and  N 2 are found in the same manner as  NO was found

MWmix   0.002  28.010    0.127  44.011   0.149 18.016   0.722  28.013  106 106   33.006 
MWmix  28.6 kg/kmol-mix
c) MWi CO: Y   0.002  28.01/28.6   0.002
Yi  i
MWmix CO 2 : Y   0.127  44.011/28.6   0.195
 kgi /kg mix  H 2 O: Y   0.149 18.016/28.6   0.094
N2: Y   0.722  28.013/28.6   0.707
NO: Y  106 106   30.006/28.6   111106



COMMENT: Note that ppmi  i 1106  and that  i  1 and  Yi  1 can often be used to

check your calculations




Copyright 2021 © McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior
written consent of McGraw-Hill Education. 2-32

, PROBLEM 2-3

Consider a gaseous mixture consisting of 5 kmol of H2 and 3 kmol of O2. Determine the H2 and
O2 mole fractions, the molecular weight of the mixture, and the H2 and O2 mass fractions.

GIVEN: Mixture with 5 kmole H2 and 3 kmole O2

FIND: χ H2 , χ O2 , MWmix , YH2 , YO2

SOLUTION:
N 5
a) i  i ;  H2   0.625
N tot 53
O2  1   H2  1  0.625  0.375
b) MWmix   i MWi   H2 MWH2  O2 MWO2
 0.625  2.016   .375  31.999 
MWmix  13.260
MWi 2.016
c) Yi  i ; YH2  0.625  0.095
MWmix 13.260
YO2  1  YH2  1  0.095  0.905

COMMENT: Even though the mole fraction of H2 is large, its low molecular weight results in its
having a small mass fraction.




Copyright 2021 © McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior
written consent of McGraw-Hill Education. 2-33

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