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Samenvatting - Scheikunde (eindexamen VWO) £2.56   Add to cart

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Samenvatting - Scheikunde (eindexamen VWO)

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In deze documenten vind je verschillende tips & tricks, formules en meer die je kunnen helpen bij het voorbereiden van het eindexamen scheikunde.

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  • October 21, 2024
  • 4
  • 2020/2021
  • Summary
  • Secondary school
  • 6
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Zuren en basen

Titratie:
− +
1. stel vergelijking van de reactie op (altijd 𝑂𝐻 of 𝐻3𝑂 )
2. bereken aantal mol toegevoegde stof (𝑀 · #𝐿)
3. bereken aantal mol oorspronkelijke stof (molverhouding)
4. bereken concentratie getitreerde stof (𝑚𝑜𝑙 ÷ #𝐿)
5. houd rekening met eventuele verdunning (× #𝑣𝑒𝑟𝑑𝑢𝑛𝑛𝑖𝑛𝑔𝑒𝑛)

pH en pOH:
+
● 𝑝𝐻 =− 𝑙𝑜𝑔[𝐻3𝑂 ]
+ −𝑝𝐻
● [𝐻3𝑂 ] = 10

● 𝑝𝑂𝐻 =− 𝑙𝑜𝑔[𝑂𝐻 ]
− −𝑝𝑂𝐻
● [𝑂𝐻 ] = 10
● 𝑝𝐻 + 𝑝𝑂𝐻 = 14

Evenwichtsvoorwaarde:
[𝑒𝑖𝑛𝑑𝑠𝑡𝑜𝑓 1]·[𝑒𝑖𝑛𝑑𝑠𝑡𝑜𝑓 2]
● 𝐾𝑧/𝐾𝑏 = [𝑏𝑒𝑔𝑖𝑛𝑠𝑡𝑜𝑓]
2
● Bij eindstof = 2𝐴 → [𝐴]

BOE-tabel:

[beginstof] [eindstof 1] [eindstof 2]

B ... 0 0

O -x +x +x

E …-x x x


1. maak tabel zoals hierboven ^ met gegeven gegevens erin (x blijft x)
2. noteer de evenwichtsvoorwaarde
3. vul gegevens in in evenwichtsvoorwaarde (x blijft x en vul Kz in volgens Binas)
4. schrijf op dat je x verwaarloost (bij … - x verdwijnt zo de x, de twee x’en boven in
evenwichtsvoorwaarde blijven)
5. bereken de x die overblijft → kan met de formule 𝑥 = 𝐾𝑧 · 𝑐𝑜𝑛𝑐𝑒𝑛𝑡𝑟𝑎𝑡𝑖𝑒 𝑏𝑒𝑔𝑖𝑛𝑠𝑡𝑜𝑓,
+
hierin is x vaak ook [𝐻3𝑂 ]
6. check of de x die je gevonden hebt minder dan 10% van je beginconcentratie is. Zo
ja: dan mag je x inderdaad verwaarlozen en ben je klaar. Zo nee: dan moet je de
abc-formule gebruiken, deze vind je in Binas (kost veel tijd dus kan je ook laten
zitten)

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