100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Previously searched by you
Previously searched by you
logo
Solution Manual Chemistry for Environmental Engineering and Science Sawyer McCarty Parkin 5th edition - Updated 2024 £25.66   Add to cart
Quickly navigate to
Preview
  2.  
  3. Chemistry For Environmental Engineer
  4.  
  5. Chemistry For Environmental Engineer
  6.  
  7. Chemistry for Environmental Engineer

Exam (elaborations)

Solution Manual Chemistry for Environmental Engineering and Science Sawyer McCarty Parkin 5th edition - Updated 2024
 1 view  0 purchase

Solution Manual Chemistry for Environmental Engineering and Science Sawyer McCarty Parkin 5th edition - Updated 2024 Complete Solution Manual

Preview 3 out of 17  pages

Document information

  • October 22, 2024
  • 17
  • 2024/2025
  • Exam (elaborations)
  • Unknown

Subjects

Written for

All documents for this subject (1)

Seller

avatar-seller
premiumbiz379

Reviews received

Content preview

Chemistry for Environmental Engineering and Science, 5th Edition

CHAPTER 2 - PROBLEM SOLUTIONS

2.1 (a) MgCO3

FW = 24.3 + 12 + 3(16) = 84.3 g/mol
MgCO3 + 2 H+ = Mg2+ + H2CO3
84.3
EW = 2 = 42.15 g/equiv
(b) NaNO3
FW = 23 + 14 + 3(16) = 85 g/mol
NaNO3 + H+ = Na+ + HNO3
85
EW = 1 = 85 g/equiv

(c) CO2
FW = 12 + 2(16) = 44 g/mol
CO2 + H2O = H2CO3
2–
Note from above: MgCO3 + 2H+ = Mg2+ + H2CO3 and H2CO3 = 2H+ + CO3
or: CaCO3 + 2H+ = Ca2+ + H2CO3
44
EW = 2 = 22 g/equiv
*Note: –
In some reactions, Z might be considered to be 1 (i.e., H2CO3 = H+ + HCO3 )

(d) K2HPO4
FW = 2(39.1) + 1 + 31 + 4(16) = 174.2 g/mol
K2HPO4 + 2H+ = H3PO4 + 2K+
174.2
EW = 2 = 87.1 g/equiv


2.2 (a) BaSO4

FW = 137.3 + 32.1 + 4(16) = 233.4 g/mol
BaSO4 + 2 H+ = Ba2+ + H2SO4
233.4
EW = 2 = 116.7 g/equiv

(b) NaCO3



2-1

, FW = 2(23) + 12 + 3(16) = 106 g/mol
NaCO3 + 2 H+ = Na+ + H2CO3
106
EW = 2 = 53 g/equiv


(c) H2SO4

FW = 2(1) + 32.1 + 4(16) = 98.1 g/mol
2–
H2SO4 = 2H+ + SO4
98.1
EW = 2 = 49.05 g/equiv
(d) Mg(OH)2

FW = 24.3 + 2(16) + 2(1) = 58.3 g/mol
Mg(OH)2 + 2 H+ = Mg2+ + 2H2O
58.3
EW = 2 = 29.15 g/equiv


10
2.3 (a) 23+17 = 0.25 for NaOH
10 10
(b) 46+32+64 = 142 = 0.0704 for Na2SO4
10 10
(c) 78+104+7(16) = 294 = 0.034 for K2Cr2O7
10 10
(d) 39+35.5 = 74.5 = 0.134 for KCl.

X
2.4 (a) 2 = 0.15 M, X = 0.30 mol KMnO4

FW = 39.1 + 24.3 + 4(16) = 127.4 g/mol
0.30(127.4) = 38.22 g
X
(b) 2 = 0.15 N, X = 0.30 equiv. KMnO4

127.4
EW = 2 = 63.7 g/equiv

0.30(63.7) = 19.11 g




2-2

, 40
2.5 Ca2+: EW = 2 = 20 g/equiv
44
meq/l = 20 = 2.2 meq/L

24.3
Mg2+: EW = 2 = 12.15 g/equiv
19
meq/l = 12.15 = 1.56 meq/L

Total Hardness = 2.20 + 1.56 = 3.76 meq/L
= 3.76(50 mg/meq) = 188 mg/lL as CaCO3


–
2.6 Note: for HCO3 , H+, and OH–, mol/L = equiv/L (Z = 1)
2–
for CO3 , equiv/L = 2(mol/L) (Z = 2)
[OH–][H+] = 10-14 ½°¾
for [H+] = 10-9.5, [OH–] = 10-4.5
pH = –log [H+] ¿°

– 118 mg/L
[HCO3 ] = 61,000 mg/mol = 1.93 x 10-3 M

2– 19 mg/L
[CO3 ] = 60,000 mg/mol = 3.17 x 10-4 M

equiv/L Alk = 1.93 x 10-3 + 2(3.17 x 10-4) + 10-4.5 – 10-7.5

Alk = 2.60 x 10-3 equiv/L (50,000 mg/equiv)
Alk = 130 mg/L as CaCO3


2.7 (a) CaCl2 + Na2CO3 = CaCO3(s) + 2 NaCl
(b) Ca3(PO4)2 + 4 H3PO4 = 3 Ca(H2PO4)2
(c) MnO2 + 2NaCl + 2H2SO4 = MnSO4 + 2H2O + Cl2 + Na2SO4
(d) Ca(H2PO4)2 + 2NaHCO3 = CaHPO4 + Na2HPO4 + 2H2O + 2CO2


2.8 (a) FeS + 2HCl = FeCl2 + H2S
(b) 3Ca2 + 6KOH = 5KCl + KClO3 + 3H2O
(c) 6FeSO4 + K2Cr2O7 + 7H2SO4 = 3Fe2(SO4)3 + Cr2(SO4)3 + K2SO4 + 7H2O
(d) Al2(SO4)3 • 14H2O + 3Ca(HCO3)2 = 2Al(OH)3 + 3CaSO4 + 14H2O + 6CO2


2.9 (a) 4Fe(OH)2 + 2H2O + O2 = 4Fe(OH)3



2-3

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller premiumbiz379. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for £25.66. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

83750 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy revision notes and other study material for 14 years now

Start selling
£25.66
  • (0)
  Add to cart