Fundamentals Of Analytical Chemistry, 10e By Skoog
Fundamentals Of Analytical Chemistry, 10e By Skoog
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Solution Manual For Fundamentals of Analytical Chemistry, 10th Edition by Skoog, All 32 Chapters Covered, Verified Latest Edition
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Fundamentals Of Analytical Chemistry, 10e By Skoog
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Fundamentals Of Analytical Chemistry, 10e By Skoog
Solution Manual For Fundamentals of Analytical Chemistry, 10th Edition by Skoog, All 32 Chapters Covered, Verified Latest Edition Contents The Nature of Analytical Chemistry Part I: Quality of Analytical Measurements Calculations Used in Analytical Chemistry Precision and Accuracy of Chemical Analy...
2-5. Why is 1 g no longer exactly 1 mole of unified atomic mass units?
Answer:
The dalton is defined as 1/12 the mass of a neutral 12C atom. With the redefinition of SI
base units in 2019, the definition of the dalton remained the same. However, the
definition of the mole and the kilogram changed in such a way that the molar mass unit
is no longer exactly 1 g/mol.
2-7. Find the number of Na+ ions in 2.75 g of Na3PO4?
Solution:
2.75 g Na PO 1 mol Na3PO4 3 mol Na 6.022 10 Na 3.03 1022 Na
23
3 4
163.94 g mol Na3PO4 mol Na
2-9. Find the amount of the indicated element (in moles) in
Solutions:
(a) 5.32 g of B2O3.
5.32 g B O 2 mol B mol B2O3 0.153 mol B
2 3
mol B2O3 69.62 g B2O3
(b) 195.7 mg of Na2B4O7 10H2O.
195.7 mg Na B O 10H O g 7 mol O
2 4 7 2
1000 mg mol Na2B4O7 10H2O
mol Na2B4O 7 10H2O
3.59 103 mol O = 3.59 mmol
381.37 g
(c) 4.96 g of Mn3O4.
mol Mn3O4
4 3 mol Mn 6.50 102 mol Mn
4.96 g Mn3O4 228.81 g Mn3O
mol Mn3O 4
(d) 333 mg of CaC2O 4.
2 mol C
g 5.20 103 mol C
333 mg CaC O
2 4
mol CaC2O4
1000 mg 128.10 g CaC2O4 mol CaC2O4
5.20 mmol
2-11. Find the number of millimoles of solute in
Solutions:
(a) 2.00 L of 0.0449 MKMnO .
4
0.0449 mol KMnO4 1000 mmol
2.00 L 89.8 mmol KMnO 4
L mol
Solutions:
(a) 16.0 mL of 0.350 M sucrose (342 g/mol)?
0.350 mol sucrose L 342 g sucrose 1000 mg
L 1000 mL mol sucrose g
16.0 mL 1.92 103 mg sucrose
3.76 10 3 mol H2O2 34.02 g H2O2 1000 mg
1.92 L 246 mg H O
L mol H2 O2 g 2 2
2-16. What is the mass in grams of solute in
Solutions:
(a) 250 mL of 0.264 M H2O2 ?
0.264 mol H2O2 L 34.02 g H2O 2
250 mL 2.25 g H 2O 2
L 1000 mL mol H2O2
(b) 37.0 mL of 5.75 104 M benzoic acid (122 g/mol)?
5.75 104 mol benzoicacid L 122 g benzoicacid
L 1000 mL mol benzoicacid
37.0 mL 2.60 103 g benzoicacid
2-17. Calculate the p-value for each of the listed ions in the following:
Solutions:
(a) Na1 , Cl , and OH in a solution that is 0.0635 M in NaCl and 0.0403 M in NaOH.
pNa log(0.0635 0.0403) log(0.1038) 0.9838
pCl log(0.0635) 1.197
pOH log (0.0403) 1.395
(c) H, Cl , and Zn21 in a solution that is 0.400 M in HCl and 0.100 M in ZnCl 2.
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