Bioo - Samenvattingen, Notities en Examens

Op zoek naar een samenvatting over Bioo? Op deze pagina vind je 17 samenvattingen over Bioo.

Pagina 2 van de 17 resultaten

Sorteer op

BIOOGY 111- C11 Osmosis and diffusion
  • BIOOGY 111- C11 Osmosis and diffusion

  • Tentamen (uitwerkingen) • 14 pagina's • 2021
  • BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion/BIOOGY 111- C11 Osmosis and diffusion
    (0)
  • €15,23
  • + meer info
Samenvatting H13 Microbioom voedingsstoffen en ingrediënten semester 2
  • Samenvatting H13 Microbioom voedingsstoffen en ingrediënten semester 2

  • Samenvatting • 3 pagina's • 2021
  • Ook in voordeelbundel
  • Samenvatting H13 Microbioom voedingsstoffen en ingrediënten semester 2, jaar 1 voedings- en dieetkunde
    (0)
  • Gratis
  • 5x verkocht
  • + meer info
Introduction to Bioorganic Chemistry and Chemical Biology: ANSweRS To CHAPTeR 6
  • Introduction to Bioorganic Chemistry and Chemical Biology: ANSweRS To CHAPTeR 6

  • Tentamen (uitwerkingen) • 8 pagina's • 2021
  • Answer 6.1 Solve the equation. Convert temperature in °C to K by adding 273. Plug the numbers into ΔG = ΔH – TΔS. Kassociation = e–ΔG/RT. This is the equilibrium constant for association, so take the inverse: Kd = 1/Kassociation. Calculated using Kd = koff/kon: Answer 6.3 when the concentration of NADH is 3 × 10–7 M, the ratio of bound to unbound alcohol dehydrogenase is 1:1. From there, the ratio of bound to unbound enzyme can easily be estimated at other concentrations of N...
    (0)
  • €17,20
  • + meer info
Introduction to Bioorganic Chemistry and Chemical Biology: Chapter 4 Answers Introduction to Bioorganic Chemistry and Chemical Biology: Chapter 4 Answers
  • Introduction to Bioorganic Chemistry and Chemical Biology: Chapter 4 Answers

  • Tentamen (uitwerkingen) • 7 pagina's • 2021
  • Answer 4.1 The bulky tert-butyl group has a strong equatorial preference, the following two conformations will be predominant. The anti isomer cannot hydrolyze through neighboring group participation; the syn isomer can hydrolyze through neighboring group participation. OCH3 -O P O O :O- anti Introduction to Bioorganic Chemistry and Chemical Biology | A4096 OCH3 -O P O O.. -O Van Vranken & Weiss | 978-0-8153-4214-4 Answer 4.2 There are two plausible mechanisms that av...
    (0)
  • €12,28
  • + meer info
Introduction to Bioorganic Chemistry and Chemical Biology: Chapter 7 answers Introduction to Bioorganic Chemistry and Chemical Biology: Chapter 7 answers
  • Introduction to Bioorganic Chemistry and Chemical Biology: Chapter 7 answers

  • Tentamen (uitwerkingen) • 6 pagina's • 2021
  • Answer 7.4 Compounds with the strongest axial donor lone pair would exhibit the strongest preference for an axial or Group Answer 7.5 In lubiprostone, the CF2 group should favor the cyclic hemiketal relative to the parent compound with CH2 Answer 7.6 the trend of faster hydrolysis of α-glucopyranosides holds for a wide range of glycosidic derivatives. Oddly, methyl α-d-glycosides (such as gluco, galacto, and xylo) hydrolyze more slowly than the corresponding β-anomers. © design by t...
    (0)
  • €12,28
  • + meer info
ANATOMY_STUDY_GUIDE_QUIZ_21050
  • ANATOMY_STUDY_GUIDE_QUIZ_21050

  • Tentamen (uitwerkingen) • 8 pagina's • 2022
  • ANATOMY_STUDY_GUIDE_QUIZ_21050
    (0)
  • €7,86
  • + meer info
bioogy revision notes
  • bioogy revision notes

  • Interview • 36 pagina's • 2021
  • simple easy notes
    (0)
  • Gratis
  • 1x verkocht
  • + meer info