Genetics 3333 Exam 3 (practice Questions and Answers) Verified
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Genetics 3333
Genetics 3333 Exam 3 (practice
Questions and Answers) Verified
In a Chi-square analysis, what general condition causes one to reject the null
hypothesis? Always assume alpha is 0.05 unless otherwise stated.
usually when the probability value is less than 0.05
when observed >&g...
Genetics 3333 Exam 3 (practice
Questions and Answers) Verified
In a Chi-square analysis, what general condition causes one to reject the null
hypothesis? Always assume alpha is 0.05 unless otherwise stated.
usually when the probability value is less than 0.05
when observed >> expected
when observed = expected
usually when the probability value is less than 0.5
usually when the probability value is less than 0.005 - CORRECT ANSWER-Usually
when the probability value is less than 0.05
The Chi-square test involves a statistical comparison between measured (observed)
and predicted (expected) values. One generally determines degrees of freedom as
________.
the sum of the two categories
one more than the number of classes being compared
One less than the number of classes being compared
ten minus the sum of the two categories
the number of categories being compared - CORRECT ANSWER-One less than the
number of classes being compared
You have the goal of creating an ideal corn crop that appeals to OU students' appetites.
OU students prefer crimson-colored kernels over those awful burnt-orange kernels that
Texas students seem to love. In order to expedite your final mass breeding, you decide
it is important to understand the inheritance pattern of kernel color. You perform a
monohybrid cross and get 910 burnt-orange to 306 crimson kernels. You thus propose
a 3:1 model to test using chi-square analysis. Calculate a chi-square value (total
deviation). Choose the closest value to the chi square you've calculated.
remember to calculate for each group and add together.
You perform a dihybrid cross to test the inheritance of two fruit fly genes: eye color and
wing morphology. You propose a 9:3:3:1 model to test using chi-square analysis. You
, set your alpha to 0.05. Your final p value ends up being 0.09. Which of the following is
correct?
There is a 9% chance that if you redid your experiment, you'd get the same or greater
amount of observed deviation from the model.
You have proven your null hypothesis.
You have data to support linkage of the two genes.
You should reject your null hypothesis. - CORRECT ANSWER-There is a 9% chance
that if you redid the experiment, you'd get the same or greater amount of observed
deviation from the model.
In a Chi-square test, as the value of the χ2 increases, the likelihood of rejecting the null
hypothesis ________.
stays the same
increases
is doubled
decreases - CORRECT ANSWER-Increases
G and E are genes in a diploid organism. The cross of genotypes GE/ge × ge/ge
produces the following progeny: GE/ge 404; ge/ge 396; gE/ge 97; Ge/ge 103. From
these data, one can conclude that ________.
the G and E loci assort independently
the G and E loci reside on the same chromosome over 50 map units apart
the G and E loci are linked
the G and E loci show complete linkage - CORRECT ANSWER-The G and E loci are
linked
G and E are genes in a diploid organism. The cross of genotypes GE/ge × ge/ge
produces the following progeny: GE/ge 404; ge/ge 396; gE/ge 97; Ge/ge 103. From
these data one can conclude that ________.
the recombinant progeny are gE/ge and Ge/ge
the recombinant progeny are Ge/Ge and gE/gE
the recombinant progeny are gE/GE and GE/ge
the recombinant progeny are GE/GE and ge/ge
the recombinant progeny are GE/ge and GE/ge - CORRECT ANSWER-The
recombinant progeny are gE/ge and Ge/ge
G and E are genes in a diploid organism. The cross of genotypes GE/ge × ge/ge
produces the following progeny: GE/ge 404; ge/ge 396; gE/ge 97; Ge/ge 103. From
these data, one can conclude that there are ________ map units between the G and E
loci.
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