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Summary BBS1005 Human Genetics and Prenatal Development €10,49   In winkelwagen

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Summary BBS1005 Human Genetics and Prenatal Development

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Summary of 41 pages for the course BBS1005 at UM (-)

Voorbeeld 4 van de 41  pagina's

  • 4 februari 2021
  • 41
  • 2018/2019
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Summary BBS1005 Human genetics, reproduction and prenatal development

Case 1
Mutations
Point mutations
1. Substitution: one base is replaced with another
a. Transition  purine with purine (A & G) or pyrimidine with pyrimidine (T & C)
b. Transversion  purine with pyrimidine or vice versa
2. Insertion: one or nucleotides is added
3. Deletion: one or more nucleotides is removed
Point mutations can be
 Silent: the same protein will be synthesized
 Missense: another amino acid will be synthesized
o Conservative: an amino acid with the same properties
o Nonconservative: a very different amino acid
 Nonsense: mutation results in the synthesis of a stop codon which will result in a very short
amino acid chain
Chromosomal mutations
1. Inversion: two parts of the chromosome are switched
a. Paracentric  centromere not included
b. Pericentric  centromere included
2. Insertion: insertion of a larger sequence into a chromosome
3. Deletion: region of the chromosome is lost
a. Terminal deletion  in terminal part of chromosome,
leads to an adhesive terminus
b. Intercalary deletion  in the interior part
c. Microdeletion  small amount (up to 5 Mb = 12 genes)
4. Duplication: region of the chromosome is doubled
a. Tandem duplication
b. Reverse tandem duplication
c. Terminal tandem duplication
5. Translocation: region of one chromosome is attached to another
chromosome
a. Nonreciprocal intrachromosomal  movement of a
chromosome segment from one location in the chromosome, to another
b. Nonreciprocal interchromosomal  chromosomal segments are exchanged between
two non-homologous chromosomes
c. Reciprocal interchromosomal  one-way transfer of a chromosomal segment to
another

DNA repair mechanisms
Mismatch repair
 Happens right after the new DNA has been made and its job is to remove and replace mis-
paired bases, which weren’t fixed during proofreading
 Steps:
1. Protein complex recognizes and binds to the mis-paired base
2. Second complex cuts the DNA near the mismatch
3. More enzymes chop out the incorrect nucleotide and a surrounding patch of DNA
4. A DNA polymerase replaces the missing section with correct nucleotides
5. DNA ligase seals the gap

,  Proteins recognise nicks (single-stranded breaks) to know which of the bases is “wrong” 
nicks are only found on newly synthesized DNA
Direct reversal
 Fix DNA by reversing the chemical reaction that caused it
 Mutations often occur because an extra group of atoms gets attached to DNA
Base excision repair
 Group of enzymes (glycosylases): each detects and removes a specific kind of damaged base
 E.g. deamination can convert cytosine into uracil, which will then match with adenine 
glycosylases detect and remove deaminated cytosine and the gap is filled by other enzymes
Nucleotide excision repair
 Remove multiple bases and replace it with the help of DNA polymerase
 Detects and corrects types of damage that distort the double helix
 Helicase cranks open the DNA to form a bubble and DNA-cutting enzymes chop out the
damaged part of the bubble  DNA polymerase replaces the missing DNA and ligase seals
Double stranded break repair
 Double stranded break = splitting the chromosome in two
 Non-homologous end joining
o The two broken ends are glued back together  messy and involves loss or addition
of nucleotides (produces mutation, but this is better than losing the entire part of a
chromosome)
 Homologous recombination
o Information from the homologous chromosome that matches the damaged one is
used to repair the break  two homologous chromosomes come together and the
undamaged region is used as a template to replace the damaged region of the
broken chromosome
 Clearer and doesn’t cause mutations, usually
 Only possible when you have the sister strand
 End of G2 phase in mitosis
 During crossing over in meiosis (prophase I)

Meiosis and mitosis

,Production of gametes
Sperm
 Primordial germ cells migrate to the testes: gonocytes  develop into spermatogonium
 Puberty: spermatogonium will perform meiosis and become a haploid sperm cell
 Sperm production in seminiferous tubules: separate from systemic circulation by blood-testis
barrier  formed by Sertoli cells, prevents hormones and constituents from affecting the
sperm, and prevents the immune system recognising the sperm as foreign
 Primary spermatocytes undergo meiosis, creating first spermatocytes and then spermatids
 Spermatids then undergo spermiogenesis and form mature spermatozoa
 When the sperm are in the female reproductive tract, capacitation takes place




Oocytes
 Primordial germ cells migrate to ovaries: gonocytes  develop into oogonium
 20 weeks: ~7 million cells  before birth: ~2 million primary oocytes due to cell death 
puberty: ~40.000 left due to artresia
 Clusters of primary oocytes surrounded by epithelial cells: follicular cells and will form
primordial follicles
 Three stages of maturation of the primary oocytes
1. Pre-antral stage: oocyte and follicular cells grow and become granulosa cells (= secrete
glycoproteins to form zona pellucida)
Surrounding connective tissue becomes theca
folliculi, LH present: secrete androgens
2. Antral stage: spaces between granulosa cells
combines and forms one fluid filled space = the
antrum. Follicles are secondary follicles and will
develop under influence of FSH, LH and oestrogen
3. Pre-ovulatory stage: meiosis I is complete: 1
secondary oocyte + 3 polar bodies
 Ovulation process: LH increases collagenase activity to
weaken the follicular wall, the ovarium wall will have
muscle contractions, and the ovum is released and
taken up into the fallopian tube via fimbriae
 Fertilisation: secondary oocyte completes meiosis II
after fertilisation; if fertilisation does not occur, the
oocyte degenerates; if it is fertilised, peristaltic
movements of the fallopian tube move the egg to the
uterus where it implants to the uterine wall

, Case 2
Capacitation of sperm cells
 Because of the changes, the sperm cell
can penetrate the zona pellucida

Fertilization
1. Spermatozoon reaches the zona
pellucida, and binds due to interaction
with a glycoprotein sperm receptor
2. The acrosome releases degradative
enzymes  sperm can penetrate in the
zona pellucida

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