100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached 4.2 TrustPilot
logo-home
Exam (elaborations)

ALEKS Basic Math Placement Test Review With Complete Solution!!

Rating
-
Sold
-
Pages
6
Grade
A+
Uploaded on
08-03-2024
Written in
2023/2024

how to find domain with a given equation - ANSWER --if a fraction, set denom. to zero, then solve -in equation, plug in 0 for x *usually can be a + or - solution* (-) + (-)= ... (-) x (-)= ... (-) divided by a (-)= ... - ANSWER -(-) (+) (+) quotient - ANSWER -division adding and subtracting fractions - ANSWER --make denoms the same -add/subtract numerators multiplying fractions - ANSWER -just multiply numerators across and denoms across and simplify dividing fraction - ANSWER -multiply by reciprocal (change second fraction to reciprocal) multiplying/dividing/adding mixed fractions - ANSWER -turn them into regular fractions (multiplying # by denom, adding it to num, keeping denom the same) and continue subtracting mixed fractions - ANSWER -*first: make denoms the same* set up as if you're subtracting two large numbers (on top and on bottom) how to solve problems like 5-2 (1/3) - ANSWER -1) make problem 5- (2 (1/3)) 2) separate : 5- 2- (1/3) to get: 3- (1/3) 3) rewrite whole #: 2+1- (1/3) 4) rewrite as: 2 + (3/3) - (1/3) to ed up with: 2 (2/3) inequality problem rule (<, >, etc like problems) - ANSWER -When *multiplying/dividing* each side by a *positive* number, the inequality sign *stays the same* When *multiplying/dividing* each side by a *negative* number, we *flip* the inequality sign.

Show more Read less
Institution
ALEKS Basic Math Placement
Course
ALEKS Basic Math Placement









Whoops! We can’t load your doc right now. Try again or contact support.

Written for

Institution
ALEKS Basic Math Placement
Course
ALEKS Basic Math Placement

Document information

Uploaded on
March 8, 2024
Number of pages
6
Written in
2023/2024
Type
Exam (elaborations)
Contains
Questions & answers

Subjects

Content preview

ALEKS Basic Math Placement Test
Review With Complete Solution!!
how to find domain with a given equation - ANSWER --if a fraction, set denom. to zero,
then solve
-in equation, plug in 0 for x
*usually can be a + or - solution*

(-) + (-)= ...
(-) x (-)= ...
(-) divided by a (-)= ... - ANSWER -(-)
(+)
(+)

quotient - ANSWER -division

adding and subtracting fractions - ANSWER --make denoms the same
-add/subtract numerators

multiplying fractions - ANSWER -just multiply numerators across and denoms across
and simplify

dividing fraction - ANSWER -multiply by reciprocal (change second fraction to
reciprocal)

multiplying/dividing/adding mixed fractions - ANSWER -turn them into regular fractions
(multiplying # by denom, adding it to num, keeping denom the same) and continue

subtracting mixed fractions - ANSWER -*first: make denoms the same*
set up as if you're subtracting two large numbers (on top and on bottom)

how to solve problems like 5-2 (1/3) - ANSWER -1) make problem 5- (2 (1/3))
2) separate : 5- 2- (1/3) to get: 3- (1/3)
3) rewrite whole #: 2+1- (1/3)
4) rewrite as: 2 + (3/3) - (1/3) to ed up with:
2 (2/3)

inequality problem rule (<, >, etc like problems) - ANSWER -When *multiplying/dividing*
each side by a *positive* number, the inequality sign *stays the same*

When *multiplying/dividing* each side by a *negative* number, we *flip* the inequality
sign.

, area and circumference of circle - ANSWER -A= pi x r^2
C= 2 x pi x r

area and perimeter of a triangle - ANSWER -A= (1/2)bh (unit squared)
P= side+side+ side

Volume and surface area of a rectangular prism - ANSWER -V=lwh (unit to the 3rd
power)
SA= 2(wl + hl+ hw)

distance formula - ANSWER -d= rate x time

percent to fraction - ANSWER -percent as numerator and 100 as denominator, then
simplify

fraction to percent - ANSWER -1) do long division with denom as outside and numerator
as inside
2) move decimal over 2 places to make it into a %
*do not forget decimal*
ORRRR
make denom 100 (multiply num and denom of original fraction by whatever to get it to
100)

how to find percent of change - ANSWER -1) change/ original amount
2) make fraction into a decimal
3) move decimal to make it a percent

how to find new price given a percentage off - ANSWER -1) subtract the given percent
by 100
2) make that number into a decimal
3) multiply decimal by amount to get new price
ORRRR
1) change percent to a decimal
2) multiply decimal by dollar amount
3) subtract that amount from the old amount to see new amount

simple interest - ANSWER -I= Prt
(p= principle/ beginning amount)
*change percent into decimal*

Compounded Interest - ANSWER -*use when problem says annually*
A= P (1+r)^t

functions... - ANSWER -can have only different inputs/x values

Borrowing for 0 and 1.... - ANSWER -0 --> 10
R181,05
Get access to the full document:

100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached


Document also available in package deal

Get to know the seller

Seller avatar
Reputation scores are based on the amount of documents a seller has sold for a fee and the reviews they have received for those documents. There are three levels: Bronze, Silver and Gold. The better the reputation, the more your can rely on the quality of the sellers work.
IMORA West Virginia University
Follow You need to be logged in order to follow users or courses
Sold
194
Member since
2 year
Number of followers
77
Documents
5079
Last sold
2 weeks ago

4,4

69 reviews

5
49
4
8
3
8
2
1
1
3

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their exams and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can immediately select a different document that better matches what you need.

Pay how you prefer, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card or EFT and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Frequently asked questions