Nucleophile - Samenvattingen, Aantekeningen en Examens

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OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS  Haloalkane to nitrile - ANSWER-nucleophilic substitution  ethanolic NaCN or KCN  heat  Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution   Excess ethanolic NH3 with no further s
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no further s

  • Tentamen (uitwerkingen) • 9 pagina's • 2024
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no further substitution HEAT under PRESSURE acyl chloride/acid anhydride to SECONDARY amide - ANSWER-Nucleophilic substitution primary amine Acyl chloride/acid anhydride to PRIMARY amide - ANSWER-Nucleophilic substitution Alkene t...
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OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS     Haloalkane to nitrile - ANSWER-nucleophilic substitution    ethanolic NaCN or KCN    heat    Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution    Excess ethanolic NH3 with no
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS   Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no

  • Tentamen (uitwerkingen) • 9 pagina's • 2024
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS   Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no further substitution HEAT under PRESSURE acyl chloride/acid anhydride to SECONDARY amide - ANSWER-Nucleophilic substitution primary amine Acyl chloride/acid anhydride to PRIMARY amide - ANSWER-Nu...
    (1)
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OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS     Haloalkane to nitrile - ANSWER-nucleophilic substitution    ethanolic NaCN or KCN    heat    Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution    Excess ethanolic NH3 with no
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS   Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no

  • Tentamen (uitwerkingen) • 9 pagina's • 2024
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS   Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no further substitution HEAT under PRESSURE acyl chloride/acid anhydride to SECONDARY amide - ANSWER-Nucleophilic substitution primary amine Acyl chloride/acid anhydride to PRIMARY amide - ANSWER-Nu...
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AQA AS CHEMISTRY 7404/2 Paper 2 Organic and Physical Chemistry Question Paper + Mark scheme [MERGED] June 2022 *JUN227404201* IB/M/Jun22/E7 7404/2 For Examiner’s Use Question Mark 1
  • AQA AS CHEMISTRY 7404/2 Paper 2 Organic and Physical Chemistry Question Paper + Mark scheme [MERGED] June 2022 *JUN227404201* IB/M/Jun22/E7 7404/2 For Examiner’s Use Question Mark 1

  • Tentamen (uitwerkingen) • 63 pagina's • 2023
  • AQA AS CHEMISTRY 7404/2 Paper 2 Organic and Physical Chemistry Question Paper + Mark scheme [MERGED] June 2022 *JUN* IB/M/Jun22/E7 7404/2 For Examiner’s Use Question Mark 1 2 3 4 5 6 7 Section B TOTAL Time allowed: 1 hour 30 minutes Materials For this paper you must have: • the Periodic Table/Data Sheet, provided as an insert (enclosed) • a ruler with millimetre measurements • a scientific calculator, which you are expected to use where appropriate. Instructions...
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OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS     Haloalkane to nitrile - ANSWER-nucleophilic substitution    ethanolic NaCN or KCN    heat    Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution    Excess ethanolic NH3 with no
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS   Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no

  • Tentamen (uitwerkingen) • 9 pagina's • 2024
  • OCR CHEMISTRY A LEVEL WITH COMPLETE SOLUTIONS   Haloalkane to nitrile - ANSWER-nucleophilic substitution ethanolic NaCN or KCN heat Haloalkane to primary amine (also makes NH4X) - ANSWER-Nucleophilic substitution Excess ethanolic NH3 with no further substitution HEAT under PRESSURE acyl chloride/acid anhydride to SECONDARY amide - ANSWER-Nucleophilic substitution primary amine Acyl chloride/acid anhydride to PRIMARY amide - ANSWER-Nu...
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CHM 219 Module 4/5/7 Exam   Questions With Revised   Correct Detailed Answers   |ALREADY GRADED A+ PASS 2024   >> BRAND NEW VERSION!!
  • CHM 219 Module 4/5/7 Exam Questions With Revised Correct Detailed Answers |ALREADY GRADED A+ PASS 2024 >> BRAND NEW VERSION!!

  • Tentamen (uitwerkingen) • 27 pagina's • 2024
  • CHM 219 Module 4/5/7 Exam Questions With Revised Correct Detailed Answers |ALREADY GRADED A+ PASS 2024 >> BRAND NEW VERSION!! 1) Dehydrohalogenation - ANSWER When the reaction occurs specifically on an alkyl halide substrate. Both H and Halogen are being eliminated from the substrate molecule. 2) E2 - ANSWER -biomolecular -one step -Nucleophile acts as a base and removes the beta H from the beta C, at the same time the electrons from the C-H bond come down ...
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Chem 210 – Reactions Questions 100% Solved!!
  • Chem 210 – Reactions Questions 100% Solved!!

  • Tentamen (uitwerkingen) • 6 pagina's • 2024
  • Reagent = Nucleophile Only - ANSWER1° = Sn2 2° = Sn2 3° = Sn1 + E1 (polar medium necessary) Reagent = Strong Nucleophile & Strong Base - ANSWER1° = Sn2 2° = E2 3° = E2 Reagent = Weak Nucleophile and Weak Base - ANSWER1°/2° = No Reaction 3°/resonance stabilized carbocation = Sn1 + E1 (polar medium necessry Reagent = Base Only - ANSWER1° = E2 or Sn2 (if unhindered and no beta-hydrogen with unhindered base) 2° = E2 3° = E2 Examples of Only Nucleophiles - ANSWERCl⁻, ...
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BCH 403 Exam 2 Questions with Complete Solutions
  • BCH 403 Exam 2 Questions with Complete Solutions

  • Tentamen (uitwerkingen) • 29 pagina's • 2024
  • Why are enzymes really good catalysts? Correct Answer-Because enzyme active sites have evolved to catalyze reactions with maximum efficiency by using several catalytic mechanisms simultaneously Enzymes exhibit maximal activity under what kind of conditions? Correct Answer-Mild conditions, like conditions that exist in cells. Why are enzymes categorized as being extremely specific? Correct Answer-Because an enzyme usually catalyzes ONLY the reaction involving "its" substrate, even though ...
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Cumulative Final Exam Review Orgo II Questions and Answers Rated A+
  • Cumulative Final Exam Review Orgo II Questions and Answers Rated A+

  • Tentamen (uitwerkingen) • 22 pagina's • 2024
  • Cumulative Final Exam Review Orgo II Questions and Answers Rated A+ 1. Carboxylic acids react with nucleophiles through what type of mechanism? Answer: Addition followed by elimination Addition followed by elimination Explanation: Carboxylic acids typically undergo nucleophilic acyl substitution. In this mechanism, the nucleophile first adds to the carbonyl carbon of the carboxylic acid (addition), forming a tetrahedral intermediate. This is followed by the elimination of a leaving group...
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Chem 210 – Reactions Questions 100% Answered!!
  • Chem 210 – Reactions Questions 100% Answered!!

  • Tentamen (uitwerkingen) • 6 pagina's • 2024
  • Chem 210 – Reactions Questions 100% Answered!! Reagent = Nucleophile Only - ANSWER1° = Sn2 2° = Sn2 3° = Sn1 + E1 (polar medium necessary) Reagent = Strong Nucleophile & Strong Base - ANSWER1° = Sn2 2° = E2 3° = E2 Reagent = Weak Nucleophile and Weak Base - ANSWER1°/2° = No Reaction 3°/resonance stabilized carbocation = Sn1 + E1 (polar medium necessry Reagent = Base Only - ANSWER1° = E2 or Sn2 (if unhindered and no beta-hydrogen with unhindered base) 2° = E2 3° = E...
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