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Samenvatting Moderne Wiskunde 11e ed havo 4 A uitwerkingen vaardigheden 1
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Moderne Wiskunde 11e ed havo 4 A uitwerkingen vaardigheden 1
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Moderne Wiskunde 11e ed havo 4 A uitwerkingen vaardigheden 4
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Vaardigheden 1Pagina ó0
1a 3(x+2)=3x+6 d A(A-6)=A2-6A
b p(1,5-p)=1,5p-p' e 7,2(2x + 1,24) = 14,4x + 8,928
6(10 - ïà=60-so f x+2(x + 1) - y*2x+2- 3x+2
7x=119 9-x=ll
x=lJ (1inks en rechts : 7) -x-z (links en rechts -9)
x+10=27 ..- 1 (links en rechts x -1)
x=11 (links en rechts -10) f 2(t+51=24
1,2-p-0,3 2t+70=24 (haakjes weggewerkt)
-p = -0,9 (links en rechts -1,2) 2t=74 (links en rechts -10)
p = 0,9 (links en rechts x -1) l- I (links en rechts : 2)
Itu=l
k = 14 (links en rechts x 2)
3a Op de plaats van het bordje moet 6 staan, want f; = 3.
b l+2x-6
2x = 5 (links en rechts -1)
x = 2ï (links en rechts : 2)
18 18
,
't +'t."t!
=-=3.dusklopt.
6
In deze vergelijking komt de variabele x twee keer voor. Dan kun je de
methode van de bordjes niet gebruiken.
b Alex krijgt nu de vergelijking 2x - 2 = 8.
G 2x-2=8
2x = 70 (links en rechts + 2)
x=5 (links en rechts : 2)
Rechts van het = teken geeft 6, 5 - 2 = 30 - 2 = 28 en links van het = teken
geeft4.5+8=20+8=28
De uitkomstenzijngelijk, dus x = 5 is de oplossing van de vergelijking.
Pagina ó1
s(2\x + 6) = JJ
2l x + 6 = 11 (bordje gelegd op 2+-rr + 6)
2, x = 5 (links en rechts -6)
x=2 (links en rechts :2\)
Controle: sQr'2 + 6) = 5 ' 11 = 55, dus klopt.
Copyright: allesvoorschool
4tr @ NoordhofÍ Uitgevers bv
, VAARDIGHEDEN 1
12-6p=9 (bordjegelegd op 12- 6p)
-6p = -3 (links en rechts -12)
p=+ (links en rechts : -6)
Controle: 12 - 6.' = \D = 3, dus klopt.
(f,, + r1'= ^^1-81
zv7- À
f,x+t=a) of lx+t=-a| (bordjeop ]x+ 1)
l*=Z\ of lx=-sl (links en rechts -1)
x=14 of x=-22 (links en rechts x 4)
Controle: Q' t+ * l)z = @+)2 = zol,dus klopt.
fI.-zz + r)2 - (+L)z = 2o|, dus klopt.
6a l4x+2=6x+10
8x +2= I0 (1inks en rechts-6x)
8x=8 (linksenrechts-2)
x=| (links en rechts : 2)
Controle: I4xl+2=16 en 6x1+10=16, dusklopt.
l7x-21=21-3x
20x-21=21 (links en rechts +3x)
20x = 42 (links en rechts +21)
---r l
zlo (links en rechts : 20)
^-
Controle: I7 . 2h - 21, = U$ en 21- 3'2h= 14fr, dus klopt.
1,2(x+3)=0,7 -4,6x
I,2x * 3,6 = 0,7 - 4,6x (haakjes weggewerkt)
5,8x * 3,6 = 0,7 (links en rechts +4,6x)
5,8x = -2,9 (links en rechts -3,6)
x = -0,5 (links en rechts delen door 5,8)
Controle: 1,2(-0,5 + 3) = 1,2. 2,5 = 3 en 0,7 - 4,6. -0,5 = 3, dus klopt.
32-57x=17 + 3(x-5)
32 - 57x = 17 + 3x - 15 (haakjes weggewerkt)
32- 5'7x = 3x * 2 (rechts getallen samengenomen)
32 - 60x = 2 (links en rechts -3x)
-60x = -30 (linksenrechts-32)
x = 0,5 (links en rechts :-60)
Controle: 32- 57.0,5 = 32-28,5 = 3,5 en 17+ 3(0,5 - 5) = 17 +-13,5=3,5,
dus klopt.
24 _a
t,
2x-9 -
2x-9=4 (bordje op 2x - 9)
2x=13 (links en rechts +9)
x=6L (links en rechts : 2)
Controle:
24 24
= 6, dus klopt.
2.6t-e 4
Copyright: allesvoorschool
@ Noordhoff Uitgevers bv 4§
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