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Exercitii rezolvate 1 Probabilitati si statistica matematica R103,10   Add to cart

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Exercitii rezolvate 1 Probabilitati si statistica matematica

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Probleme de tipul celor la examen, acoperind toata materia cu toate explicatiile necesare pentru a lua o nota buna (eu din astea am invatat pentru examen si am luat 8)

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  • March 26, 2021
  • 11
  • 2020/2021
  • Class notes
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TUTORING PROBABILITĀTI
Varianta D
a
su se
2
12.11
1. al Not. X - evenimentul de
obţine 2 bile
negre
Ai - evenimentul ca extragerea
fac
din wrna i, i = 1,3
Plail = 73 * i = 1,3 3
P(xl AA)
C3.co
G
Cie
L 2 bile negre extrase din cerna 1
Urna a
3 albe 1 noi veem 2 extrageri
cu o albe si z negre
P(x1 Azl = P(Na).(PNZIN,) = & 7
4 albe
2
9 negre
7
14
33
L wena 2
2
8 negre
15
28
formula preb.
totale
(=m
is
1/3 lei
28
formula lui
PIXIA3) = Paninne) = P(NA. PIN.IN.) - 5 .
(A., A2, A3) formează partiţie
a evenimentului sigur
> P(x) = È PIAC) - P(x1A:)
tegen )
by P(A31x)
Plas) · P(x1 A3) 123 -1528
Beyes
P (*)
731%+ 1/3+1/28
probabilitatea ca extragerea sa e din wina 3
cu Mix) si D(x) nite
inegalitatea
Cebáşev fi fi

,w
i1
Dly)
MlY) = m( @xi) = M(xi) = 100.n
Tlxi)
abaterea medie patrati'co , Dixi) = 5?(X3)
=> D (Xi) = 400²
DLY) = DLE Xi)
È Dixi) = 400?1
X;- v.a.indep.
Plo,9 M(Y) EYE 11 MLY))
P(ly-Mlyll5o, 1 Mey")>, 1-
0,01.1277) E?
D(Y)
=> Det. N EIN* a. i.
0,04.M217)
400².n
Le> 0,27
col.leo?n?
n> 8000 on € [8000,00)
b) Teorema Limită Centrală (T.C.L)
Dacă Xa, X2, ..., Xn v.a. indep. . si Yn
= E Xi atunci
Yn - M(Yu) converge in repartiţie la
T(Yu)
(
nool
Z. cu repartiţia normală standard (0,1)
(=> 0,2 >
1600 1.5n
i=1
v.a.
V. a
(y) = ID;
4oo wa ? => FLY)= 460013
n = 80
=
-)
=
MLY!
loon = 8000
Plog Mly) {y < 2,1 MlY))
- P/0,9 MCY) - MLY)
Y-MCY) 1, 1M(Y) - MIX)
T(Y)
Tly)
T.C.L
P
d
9.8000
<
16005
Tly)
1600 vs

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