Exam (elaborations)
PYC 3704 Assignment 1 and 2 solutions 2021
- Course
- PYC 3704 (PYC2704)
- Institution
- University Of South Africa (Unisa)
Assignment 1 and 2 solutions for Pyc
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Assignment 1 PYC 3704 2021QUESTION 1 QUESTION 2
OPTION 2 OPTION 4
QUESTION 3 QUESTION 4
OPTION 3 OPTION 4
QUESTION 5 QUESTION 6
OPTION 3 OPTION 3
QUESTION 7 QUESTION 8
OPTION 2 OPTION 2
QUESTION 9 QUESTION 10
6
P ( ¿ )= =0.400 OPTION 2
15
OPTION 2
QUESTION 11 QUESTION 12
δ 50
= =10 p ( x )=1−0.53=0.47
√ n √25
OPTION 4 OPTION 4
QUESTION 13 QUESTION 14
1
P ( HH ) = =0.25 OPTION 2
4
OPTION 2
QUESTION 15
In order to answer this question and question 16 we need to calculate the probability of finding a
student with better marks. A high probability means many students did better than him.
Mathematics ( 56−42
P ( x>56 )=P z >
6 )
=P ( z >2.33 ) =0.01
54−54
P ( x>54 )=P ( z>
4 )
Science =P ( z> 0 )=0.5
6 2−50
P ( x> 62 )=P ( z >
8 )
Geo =P ( z >1.5 ) =0.067
, 56−42
History (
P ( x>56 )=P z >
6 )
=P ( z >2.33 ) =0.919
OPTION 1
QUESTION 16
56−42
History (
P ( x>56 )=P z >
6 )
=P ( z >2.33 ) =0.919=0.9
OPTION 4
QUESTION 17 QUESTION 18
OPTION 3 OPTION 1
QUESTION 19
P ( 25< x< 56 )=P ( 25−40
10
<z<
50−40
10 )
=P (−1.5< z <1 )=0.8413−0.0668=0.7745
OPTION 2
QUESTION 20
14−20
Z= =−0.75
6
OPTION 3
QUESTION 21
P ( z←0.75 )=0.2266
OPTION 1
QUESTION 22 QUESTION 23
OPTION 4 OPTION 2
QUESTION 24 QUESTION 25
OPTION 1 OPTION 4
QUESTION 26
OPTION 2
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