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- University Of South Africa (Unisa)
this is a Mae201K assignment 02
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Question 11.1 Level 0- Visualization
Students are able to – Identify figures individually
- Identify figures visually
- Name the figures
Level 1 – Analysis
Students are able to – class the figures
- recognize properties are characteristics of the classed
figures
Level 2 –Informal Deduction
Students are able to – to give definitions of the classes of figures
- notice and formulate logical relationship between
Properties
1.2.1 At this level pupil use visual perception and nonverbal thinking. They
recognize geometric figures by their shape as “a whole” and compare it with
everyday things.
1.2.2 At this level student start analyzing and naming of geometric figures. They
do not see relationships between properties, they think all properties are
important.
,1.2.3 At this level student perceive relationships between properties and figures.
They create meaningful definitions.
1.3 * Spatial sense refers to a person’s instinct to know about shapes and the
relationship between them.
* It includes the ability to mentally visualize objects and spatial relationships (to
turn things around in one’s mind)
* It also includes the familiarity with geometric descriptions of objects and
position.
* Spatial sense is considered a core area of mathematical study, like numbers.
Question 2
Statement True/False
1. All trapezoids are quadrilaterals. False
2. All parallelograms are quadrilaterals. True
3. All rhombuses have only one set of equal-length sides. False
4. All rectangles are quadrilaterals. False
5. All squares have only one set of parallel sides. False
6. All rectangles are squares. False
7. All rhombuses are squares. True
8. All squares are parallelograms. True
9. All rhombuses are parallelograms. True
10. All quadrilaterals have four sides. True
Question 3
3.1 An obtuse triangle
3.2 Parallel lines
3.3 Deductive reasoning
3.4 Pentagon
3.5 Axiom
, Question 4
ABC is a right angle triangle with angle A=45⁰
To find determine a size of angle triangle
So, angle B=90⁰
Given angle A=45⁰
Since the sum of three angle of a triangle is 180⁰
Angle c = 180⁰ - (angle A + angle B)
= 180⁰ - (45⁰ + 90⁰)
= 180⁰ - 135⁰
= 45⁰
Question 5
5.1 Answer – hence
Written expressions
Solution
in ABC,
since Ѳ = opp
Hyp
Since × = CB
AC
In ABC,
Sin × = DB
AB
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