TEST BANK FOR Computer System Architecture 3rd Edition By M. MORRIS MANO
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Exam (elaborations) TEST BANK FOR Computer System Architecture 3rd Edition By M. MORRIS MANO (Solution manual)
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TEST BANK FOR Computer System Architecture 3rd Edition By M. MORRIS MANO
Institution
Harvard University
Book
Computer System Architecture
Exam (elaborations) TEST BANK FOR Computer System Architecture 3rd Edition By M. MORRIS MANO (Solution manual)
SOLUTIONS MANUAL
M. MORRIS MANO
COMPUTER SYSTEM
ARCHITECTURE
Third Edition
- 3 -
TABLE OF CONTENTS
Chapter 1 ……………………………………………………………�...
TEST BANK FOR Computer System Architecture 3rd Edition By M. MORRIS MANO
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- 1 - SOLUTIONS MANUAL M. MORRIS MANO COMPUTER SYSTEM ARCHITECTURE Third Edition - 3 - TABLE OF CONTENTS Chapter 1 ……………………………………………………………………………… 4 Chapter 2 ……………………………………………………………………………… 11 Chapter 3 ……………………………………………………………………………… 16 Chapter 4 ……………………………………………………………………………… 20 Chapter 5 ……………………………………………………………………………… 26 Chapter 6 ……………………………………………………………………………… 34 Chapter 7 ……………………………………………………………………………… 45 Chapter 8 ……………………………………………………………………………… 51 Chapter 9 ……………………………………………………………………………… 59 Chapter 10 ……………………………………………………………………………. 63 Chapter 11 ……………………………………………………………………………. 80 Chapter 12 ……………………………………………………………………………. 89 Chapter 13 ……………………………………………………………………………. 95 - 4 - CHAPTER 1 1.1 A B C A•B•C (A•B•C)' A' B' C' A'+B'+C' 0 0 0 0 1 1 1 1 1 0 0 1 0 1 1 1 0 1 0 1 0 0 1 1 0 1 1 0 1 1 0 1 1 0 0 1 1 0 0 0 1 0 1 1 1 1 0 1 0 1 0 1 0 1 1 1 0 0 1 0 0 1 1 1 1 1 1 0 0 0 0 0 1.2 A B C A⊕B A ⊕B⊕C 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 0 0 1 1 1 1 0 0 0 1 1 0 1 0 0 1 1.3 (a) A + AB = A(1 + B) = A (b) AB + AB' = A(B + B') = A (c) A'BC + AC = C(A'B + A) = C(A' + A) (B + A) = (A + B)C (d) A'B + ABC' + ABC = A' B + AB(C' + C) = A'B + AB = B(A' + A) = B 1.4 (a) AB + A (CD + CD') = AB + AC (D + D') = A (B + C) (b) (BC' + A'D) (AB' + CD') = ABB'C' A'AB'D BCC'D' A'CD'D+++ 00000= 1.5 (a) (A + B)' (A' + B') = (A'B') (AB) = 0 (b) A + A'B + A'B' = A + A' (B + B') = A + A'= 1 1.6 (a) F = x’y + xyz’ F' = (x + y') (x' + y' + z) = x'y' + xy' + y' + xz + y'z = y' (1 + x' + x + z) + xz = y'+ xz (b) F•F' = (x'y + xyz') (y' + xz) = 0 + 0 + 0 + 0 = 0 (c) F + F' = x'y + xyz' + y' + xz (y + y') = x'y + xy(z' + z) + y' (1 + xz) = x'y + xy + y' = y(x' + x) + y' = y + y' = 1 =
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