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CHEM 120 Unit 4 Midterm | Questions and Answers | (Latest Update) | 100% CORRECT SOLUTIONS. R195,00   Add to cart
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CHEM 120 Unit 4 Midterm | Questions and Answers | (Latest Update) | 100% CORRECT SOLUTIONS.
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  • CHEM 120
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CHEM 120 Unit 4 Midterm 1. The correct isotope symbol for the isotope containing 1 proton and two neutrons – He 2. Which are the elements with the following electronic configuration: 1s2 2s 2 2p6 3s1 – Sodium 1s2 2s2 2p5- Fluorine 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 – Geremanium (Ge) 3. Provide ...

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  • November 11, 2021
  • 7
  • 2021/2022
  • Exam (elaborations)
  • Questions & answers

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  • the correct isotope symbol for the isotope containing 1 proton and two neutrons – he
  • a gas is enclosed in a 100 l tank at 350 mm hg
  • chem 120 unit 4 midterm questions and answers

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  • Chamberlain College Of Nursing
  • CHEM 120
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CHEM 120 Unit 4 Midterm



1. The correct isotope symbol for the isotope containing 1 proton

and two neutrons – He

2. Which are the elements with the following electronic

configuration:

1s2 2s2 2p6 3s1 – Sodium

1s2 2s2 2p5- Fluorine

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 – Geremanium (Ge)

3. Provide 4 examples of substances with ionic bonds


LiF - Lithium Fluoride, LiCl - Lithium Chloride, LiBr – Lithium

Bromide, LiI - Lithium Iodide, Nacl,Calcium Nitrate

5. Name the following:

N2S3 - dinitrogen trisulfide

NaCl – Sodium Choloride

P4O10- Phosphorus pentoxide

NaNO3- Sodium nitrate

Cl2O3- Dichlorine trioxide

6. A gas is enclosed in a 10.0 L tank at 350 mm Hg pressure. If the

gas is pumped into a 23.00 L vessel, what is the new pressure

10.0 L×350 mmHg 10.0 × 350mmHg 3500 mmHg
= =
23.00 L 23.00 23
This study source was downloaded by 100000829957125 from CourseHero.com on 11 -10-2021 22:28:54 GMT -06:00


https://www.coursehero.com/file/79913941/midterm-questions-docx/

, 152.173 mmHG




7. The molarity of a solution that contains 12.5 g of KClO3 in 3.2

liter of solution is

moles of solute
Molarity = ; K- 39.10 + Cl-35.45 + O-
volume of solution

16(3)-48; KClO3= 122.55 g/mol

12.5 g×1 mol 12.5 mol
M= = = 0.102 mol
122.5 g 122.5

0.102mol
= 0.032 M
3.2 L




8. What other compound could also be added in order to make a

buffered solution with each of the following:

H3PO4 - H2PO3

CH3COOH - CH2CO 2-

H2CO3 - HCO 2-

9. Balance: C2H4 + O2 → CO2 + H2O

First take a look at the equation and see how many elements there

are, in this case we have 3 different elements; Carbon, Hydrogen

and Oxygen. To balance the equation start off by balancing the




This study source was downloaded by 100000829957125 from CourseHero.com on 11 -10-2021 22:28:54 GMT -06:00


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