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Memorandum for mathematics literacy paper 1 2021

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Memorandum for mathematics literacy paper 1 2021

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  • November 12, 2021
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  • 2021/2022
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allyssaperumal1
Mathematics Literacy Paper 1 Memo
Question 1
1.1.1. Fuel price increase = 1.258 -0.8 = 0.458 US dollars
1
1.1.2. 11.14 = 0.0897 ≈ 0.09

1 Botswana pula = 0.09 US dollar

1.1.3. Angola, Namibia & Botswana

1.1.4. 1.258, 1.061, 0.87, 0.796, 0.732, 0.254
5
1.1.5. = 0.833
6




1.2.1. Electricity

1.2.2. Limpopo
764.59
1.2.3. (a) 764.59 𝑐/𝑙= 𝑅/𝑙 = 𝑅7.6459 𝑝𝑒𝑟 𝑙𝑖𝑡𝑟𝑒
100

(b) R 7.6459/per litre × 12.5 litres = R95,57

1.2.4. Solar power, nuclear energy, wind energy, fossil fuels



1.3.1. Survey, Questionnaire

1.3.2. Classify and organize data

1.3.3. Categorical

1.3.4. Value Added Tax

1.3.5. A book store



Question 2
2.1.1. Ballon/residual payment

2.1.2. Deposit = 5% of R215 100= R215 100 x 5% = R10 755

2.1.3. Ratio = 72:48

Simplest form of ratio= 3:2

2.1.4. Ford Figo

2.1.5. Total cost = Total value of monthly installments + admin fees + residual value

Total value of monthly installments = R3 345.00 x 48 = R160 560

Admin fees=2.08 % of R3 345.00 x 48 months = (R3 345 x 2.08%) x 48 =R3 339.65

, Residual value = R 116 759

Total cost = R160 560 + R3 339.65 +R116 759 = R280 658.65

2.1.6. Value after first year: R60 000+ R60 000x4.3%= R62 580

Value after second year: R62 580 + R62 580x5.1% = R65 771.58

Residual value for Ford Figo = R215 100 x 30%=R64 530

Her statement is correct

2.2.1. 3

2.2.2. ABC Made For You S

2.2.3. 𝑇𝑜𝑡𝑎𝑙 = 𝑅355.65 + 𝑅260 + 𝑅337.35 = 𝑅953

VAT = R953 x15% = R142.95

2.2.4. Total amount due = R953 +R142.95 = R1238.95= A

2.2.5. There is no/zero probability of randomly selecting a cellphone contract that is not from ABC

Question 3
3.1.1. 29 March 2021

3.1.2. one hundred and twenty eight million metres cubed

3.1.3. Kwa Zulu Natal

3.1.4. Free State

𝑠𝑢𝑚 𝑜𝑓 𝑣𝑎𝑙𝑢𝑒𝑠
3.1.5. 𝑚𝑒𝑎𝑛 = = 83 %
𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑣𝑎𝑙𝑢𝑒𝑠

Sum of values =D%+99%+101%+73%+88%+89%+82%+105%+D%
=2D+637%
Number of values = 9
2𝐷 + 637%
83% =
9
83 × 9 = 2𝐷 + 637%
747% = 2𝐷 + 637%
747% − 637% = 2𝐷
110% = 2𝐷%
110%
𝐷= = 55%
2

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