Exam (elaborations)
MIP1502 EXAM PACK 2023
- Course
- MIP1502 (MIP1502)
- Institution
- University Of South Africa
LATEST QUESTIONS WITH WELL ELABORATE ANSWERS
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MIP1502EXAM
PACK 2023
, Nuha Gallie
Student number: 67814409
Assignment 2: MIP1502
Unique number: 164948
Question 1
1.1 1.1.1 Term- it is either a single number or variable, or the product of several numbers or
variables. Terms are separated by a + or – sign in overall expression.
1.1.2 Pattern- Sequences that repeat according to rules. Sometimes patterns are known as
sequences.
1.1.3 Functions- A relation between a set of inputs having one output each. A function I a
relationship between inputs where each output ir related to exactly one output.
1.2 We determine the number pattern with a constant difference or constant ratio in a numeric
patterns. To find the next answer in a numeric patterns, we simply add and subtract. We
identify a number pattern with a constant ratio in geometric patterns. We multiply and
divide to find the next solution in geometric patterns.
1.3 The capacity to notice and develop patterns allows us to make predictions based on our
observations; this is a crucial talent in arithmetic. Understanding patterns helps
youngsters prepare for understanding complicated number ideas and mathematical
processes.
1.4 1.4.1 5² – 4² = 9
1.4.2. Yes
1.4.3 Tn = a + (n - 1)d
1.4.4 Tn = a + (n – 1)d
a=3
n=4
d=2
T4 = 3 + (4 – 1)2
T4 = 9
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, Question 2
2.1 2.1.1 4; 9; 14 …
(i) first term- 4
next four terms- 19; 24; 29; 34
(ii) 5
(iii) 5n - 1
(iv)
Input 1 2 3 4 5
Output 4 9 14 19 24
(v) Graph
30
25
20
15
10
5
0
1 2 3 4 5
2.1.2 -6; …; 3; …; 15; …
(i) first term- -6
next four terms-
(ii)
(iii)
(iv)
Input 1 2 3 4 5
Output
This study source was downloaded by 100000855277659 from CourseHero.com on 05-26-2023 14:11:01 GMT -05:00
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, (v) Graph
2.2 2.2.1
(i) Each term is growing by 2 triangles.
(ii) Table
1 2 3 4 5
2 4 6 8 10
(iii) In the first frame there are two triangles. In the second term, two more triangles were
added resulting in four triangles. In the third term, two more triangles were added
resulting in six triangles.
(iv) Tn = a + (n-1)d
Tn = 2 + (n – 1)2
Tn = 2 + 2n – 2
tn = 2n
(v) T10 = 2(10)
T10 = 20 building blocks
(vi) T100 = 2(100)
T100 = 200 building blocks
2.2.2
(i) Each term is growing by 2 triangles.
(ii) Table
1 2 3 4 5
1 3 5 7 9
(iii) In the first term there is one triangle. In the second term, two more triangles were
added resulting in three triangles. In the third term, two more triangles were added
resulting in five triangles.
(iv) Tn = a + (n – 1)d
Tn = 1 + (n – 1)2
Tn = 1 + 2n – 2
Tn = 2n - 1
(v) Tn = 2n – 1
T10 = 2(10) – 1
T10 = 19 building blocks
(vi) T100 = 2(100) – 1
T100 = 199 building blocks
2.2.3
(I) The difference are increasing from 3 to 4 to 5 to 6 to 7. the general patterm is the
difference of consecutive numbers.
(ii)
1 2 3 4 5
4 8 13 19 26
(iii)
This study source was downloaded by 100000855277659 from CourseHero.com on 05-26-2023 14:11:01 GMT -05:00
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