Exam (elaborations)
MIP1502 ASSIGNMENT 3 2023
- Course
- MIP1502 (MIP1502)
- Institution
- University Of South Africa (Unisa)
MIP1502 ASSIGNMENT 3 2023
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By: thabelokwinda1 • 1 year ago
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MIP1502ASSIGNMENT 3 2023
Assignment 3: Compulsory
Contributes 25% to the final pass mark.
Unique number: 787060
Due date: 04 July 2023
[Email address]
, Assignment 3: Compulsory
Contributes 25% to the final pass mark
Unique number: 787060
Due date: 04 July 2023
Question 1
1.1 If Lize would continue counting 3; 8; 13; ….
1.1.1 What is the 100th number that she will count? Show Lize how to calculate
the 100th number instead of actually counting all the way up to the 100th
number. (6)
The pattern is that Lize is adding 5 to each number in the sequence. So, to find the
100th number, we can start with the first number (3) and add 5 repeatedly until we
reach the 100th number.
First number: 3
Second number: 3 + 5 = 8
Third number: 8 + 5 = 13
Fourth number: 13 + 5 = 18
...
98th number: 3 + (97 x 5) = 488
99th number: 3 + (98 x 5) = 493
100th number: 3 + (99 x 5) = 498
Therefore, the 100th number that Lize will count is 498.
1.1.2 Will Lize count 996? Explain your reasoning (4)
No, Lize will not count 996. If we examine the sequence, we can see that it only
contains odd numbers. This is because we are starting with an odd number (3) and
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