100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Previously searched by you
Previously searched by you
logo
MAT1503 ASSIGNMENT 4 ANWERS 2023 R50,00   Add to cart
Quickly navigate to
Preview
  2.  
  3. University Of South Africa (Unisa)
  4.  
  5. MAT1503 - Linear Algebra (MAT1503)

Other

MAT1503 ASSIGNMENT 4 ANWERS 2023

3 reviews
 152 views  7 purchases

MAT1503 LINEAR ALGEBRA I ASSIGNMENT 04 Due date: Thursday, 20 July 2023 Total Marks: 100 ONLY FOR YEAR MODULE This assignment covers chapter 2 & 3 of the prescribed book as well as the study guide, it is based on Study Units 2.1, 2.2, 2.3 & 3.1

Preview 3 out of 25  pages

Document information

  • July 11, 2023
  • 25
  • 2022/2023
  • Other
  • Unknown

Subjects

  • mat1503 assignment 4 anwers 2023

Written for

All documents for this subject (136)

3  reviews

review-writer-avatar

By: denismariette • 1 year ago

review-writer-avatar

By: khumalosakhile93 • 1 year ago

review-writer-avatar

By: kbtroberts • 1 year ago

Seller

avatar-seller
GoldenKey

Reviews received

Content preview

Total Marks: 100

ONLY FOR YEAR MODULE This assignment covers chapter 2 & 3 of the prescribed book as well as the
study guide, it is based on Study Units 2.1, 2.2, 2.3 & 3.1



Question 1

(1.1) Let's find the matrix E1:



E1 =

[1 0 0]

[0 1 -2]

[0 0 1]



Performing the operation (3) R2 ←− R2 − 2R1, we have:



E1A =

[1 0 0]

[0 1 -2]

[0 0 1]

*

[2 -1 1]

[3 1 -1]

[1 -3 k]

,=

[2 -1 1]

[3 1 -1 - 2(2 -1 1)]

[1 -3 k]



=

[2 -1 1]

[-1 3 -3 -2 -1 2]

[1 -3 k]



=

[2 -1 1]

[-1 3 -3 -2 -1 2]

[1 -3 k]



=B



Now, let's find the values of k for which a33 = a23:



a33 = a23

1 = -3

This is not possible, so there are no values of k in the range [-1, 0] that satisfy the condition.



(1.2) Let's find the matrix E2:



E2 =

[0 0 1]

[0 1 0]

[1 0 0]



Performing the operation (3) R1 ←→ R3, we have:

, A=

[0 0 1]

[0 1 0]

[1 0 0]

*

[2 -1 1]

[3 1 -1]

[1 -3 k]



=

[1 -3 k]

[3 1 -1]

[2 -1 1]



=C



So, the matrices E2 and C are:



E2 =

[0 0 1]

[0 1 0]

[1 0 0]



C=

[1 -3 k]

[3 1 -1]

[2 -1 1]



Question 2

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through EFT, credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying this summary from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller GoldenKey. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy this summary for R50,00. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

59325 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy summaries for 14 years now

Start selling
R50,00  7x  sold
  • (3)
  Buy now