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MAT2611 Assignment EIGHT 2023

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UNISA Linear Algebra MAT2611 Assignment EIGHT of 2023 solutions.

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  • July 25, 2023
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MAT2611 ASSIGNMENT 8 2023

Problem 27

Let 𝐴 be an 𝑛 × 𝑛 matrix, where 𝑛 ≥ 2, 𝑛 ∈ ℕ

Given that 𝐴 is symmetric and orthogonal.

Since 𝐴 is symmetric then 𝐴𝑇 = 𝐴 (1)

Since 𝐴 is orthogonal then 𝐴𝑇 𝐴 = 𝐼𝑛 (2)

On equation (1) to multiply both sides by 𝐴

𝐴𝑇 = 𝐴

𝐴𝑇 𝐴 = 𝐴𝐴

𝐴𝑇 𝐴 = 𝐴2

𝐴2 = 𝐴𝑇 𝐴

To apply the result on equation (2)

𝐴2 = 𝐼𝑛

Let 𝜆 be an eigenvalue of 𝐴.

Therefore, 𝜆2 is an eigenvalue of 𝐴2

To find the eigenvalues 𝛼 of 𝐴2

𝐴2 𝒗 = 𝛼𝒗 where 𝒗 is an 𝑛 × 1 eigenvector of 𝐴2

Now, 𝐴2 = 𝐼𝑛 , therefore:

𝐼𝑛 𝒗 = 𝛼𝒗

𝒗 = 𝛼𝒗

𝒗 − 𝛼𝒗 = 𝟎

(1 − 𝛼)𝒗 = 𝟎

Eigenvectors may not be zero vectors, therefore:

1−𝛼 =0

𝛼=1

The only possible eigenvalue of 𝐴2 is 1

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