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Solution Manual of Open Channel Flow 2e by M. Hanif Chaudhry R236,40   Add to cart

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Solution Manual of Open Channel Flow 2e by M. Hanif Chaudhry

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  • Course
  • Fundamentals of Open Channel Flow
  • Institution
  • Fundamentals Of Open Channel Flow
  • Book

Solution Basic concepts 1 2. Conservation laws 13 3. Critical flow 31 4. Uniform flow 42 5. Gradually varied flow 59 6. Computation of gradually varied flow 78 7. Rapidly varied flow 110 8. Computation of rapidly varied flow 141 9. Channel design 143 10. Special topics 158 11. Unsteady fl...

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  • September 6, 2023
  • 214
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers
  • Fundamentals of Open Channel Flow
  • Fundamentals of Open Channel Flow
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CONTENTS Chapters Topics pages 1. Basic concepts 1 2. Conservation laws 13 3. Critical flow 31 4. Uniform flow 42 5. Gradually varied flow 59 6. Computa tion of gradually varied flow 78 7. Rapidly varied flow 110 8. Computa tion of rapidly varied flow 141 9. Channel design 143 10. Speci al topics 158 11. Unsteady flow 176 12. Gover ning equations for 1 -D flow 183 13. Numerical methods 191 14. Finite-difference methods 193 16. Sediment transport 201 17. Special topics 205 Solution Manual for Fundamentals of Open Channel Flow 2e by M. Hanif Chaudhry 1 Chapter 1 BASIC CONCEPTS 1.1 (i) Rectangular section A = B0Y P = 2Y+B 0 B = B 0 R = A/P = B 0Y/(2Y+B 0) D = A/B = B 0Y/ B 0 = Y (ii) Trapezoidal section A = B 0Y+ 2Y(SY/2) = Y(B 0 + SY) P = B0 +2Y S(S2+1) R = A/P = Y(B 0 + SY)/ [B0 +2Y S(S2+1)] B = B 0 +2SY D = A/B = Y(B 0 + SY)/ (B0 + 2SY) (iii) Triangular section We may use the same equation as that in the case of trapezoidal section with B 0 = 0. Thus, D = Y/2 (iv) Partially full circular section A = r
2θ/2 +2 (rCos α)/2 (Y -D0/2) = ( )( )α θ rCos DY D 2/ 8/02
0 − + Y = D 0/2 + (D0/2) Sin α A = D o2 θ /8 + D o Sin α C os α Bo Y S Y 1 Bo Bo Chapter 1 2 (v) Standard horseshoe section: Length KB ( ) )3(258186.0)2()1( 58186.0
2218787811
2222
2
0 2
0____
22____ ____ ____
2_____
2_____
2____
22____
02
0_____
2_____
2_____0 0____0_____02
0 2
02_____2_____ _____0__________ _____ _____
−−−−−−−−

− − =

− − = − =−−−−−−

− − = − =−−−−−−− =

− ==


− =

− =

−

==− =
KBdd KCKB OB OC OK FC KCKBd d KF FC KCd d OCd MCddd GM CG MCd OMOM MC OM ( )
( )
)
2Sin sin -1(8D
BA D 2sin D)2 2 ( cosr 2 cosr 2 B )sin 1(4θDrθ P2πθ0 θsinθ8DA2αsin ) (2α sin θsin and π 2α θ But 2αsinθ8Dcosα sinα4D 8θDA
ooo2
o2
o2
o2
o
θθ θθ π θαθθπ
− = == − = =− = =≤≤ − =−= + =+ =+ = + = θ θ Y D0 B Chapter 1 3 ( )
0 00 02
02
0 02
0_____
20 00____
0____2____ ____
02
0 2
0____
2____
02
02
02____
0 2
02_____
02
0
59.48 295.2424114377.02822875.0 04114377169281.0 088562.0411438.0 088562.02088562.0438856.0 2233856.0 )3( )2(
= = == == − − == − = =

− + − = − + −

− − =

− −
LL LSind CC d KCd d d d KCd ddOK d KBKB KBddd KB KBd d dKBdd KB d d and
θθ θ The standard horse sho e section is divided into three sectio ns, i.e., upper section, middle section and lower section. (a) Upper section π ≤ θ
u ≤ 2 π Flow area, A = ( )8 82
02
0 DSinD
u uπθ θ − − Wetted perimeter, P = 20θD Hydraulic radius, R = A/P = 

−θθSin D140 Top water surface, B = D 0 Sin (θ/2) Hydraulic depth, D = A/B = 


−
)2/( 80
θθ θ
SinSin D (b) Lower section 0 ≤ θ
L ≤ 48.590 Flow area, A = ( ) ( )θ θ θ θ SindSinD
L L − = −2 82
02
0 Wetted perimeter, P = 00
2dDθθ=

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