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Sumario función lineal
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Función lineal, explicación completa
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Objetivo * frsionensal=
nombre:Alexa salced
CUUP0:1
Fecha:06/02'2022
o
I Trazar el gráfico de una recta dada su ecuación en
forma pendiente -
interseccion.
-
gráfico la recta
y
-
=
Ix S
+
ejercicios:
*
·*
gráfico
2x
* necesitamos almenos 2 puntos para trazar el de las rectas
1.
= 2
+
primero, elegimos algunos valores de luego evaluamos
5 x 5
-
x. -
y
= +
para los valores de X.
x y 2x 2(x,y)
=
+
gy 3.0 2 2(0,2)
=
Ix 5(x,y)
+
=
xy
=
- +
y -
5510,5) por 24 3.2 2
(2.E)
=
0
=
multiplicamos
+ =
-
asi que valores
usamos y
3 (1,5)
21 =
5.25 (2,1) -y 3. 2
=
multipios
+ =
que son de 2.
y -
=
5.2,(0,3) 2.y
=
-
5x -
obtenemos la respuesta al marcar los 3 puntos y
xy -
5x e(x,y)
=
tracar atravies an
-
recta ave los
una 5.0
=
0
04 -
-
2
x
*
x
5 y 5.5- 7 S
=
-
5.10 1 6
=
10 - -
y -
*
repasarconresolver
e
a
1
identificar soluciones de una ecuación lineal en variables.
Determinar sicada par ordenado es una solución de y 2.
=
I liragio I ima)./acenoiasa-
ordenado esunasolucion
Determina sicada par de
des una solucion
(x, y)
Si NO
(7(7) 6(5) 19 19 30 17 719
= - - =
- -
-consine
-
- ( =(2) -
6) - 1) 14=
+
6
20
=
<z( 5) 6( 3) 35 =
=
-
18
- - -
+
Hallar una pendiente dado el gráfico de una recta en una cuadricula
pendiente recta:
I Hallar la de la siguiente
19 pendiente de una recta mide su inclinacion.
dados dos puntos
(X1, 41) y(Xz, yz) en una recta, utilizamos la siguiente formula.
eleracion =
42-4
X pendiente=
recorrido x 2 -
x1
A observemos que la elevación es el cambio en la coordenada y el
recorrido es el cambio en la coordenada X.
En este problema tenemos una recta que atraviesa tanto (2,3) como (2,-2).
* podemos fijar (X1,y1) (2,3)y(X2,y2) 2)
=
(0, >
= -
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