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APM3715 ASSIGNMENT 1 SOLUTIONS 2024 UNISA NUMERICAL METHODS FOR CIVIL ENGINEERS R350,00   Add to cart

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APM3715 ASSIGNMENT 1 SOLUTIONS 2024 UNISA NUMERICAL METHODS FOR CIVIL ENGINEERS

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APM3715 ASSIGNMENT 1 SOLUTIONS 2024 UNISA NUMERICAL METHODS FOR CIVIL ENGINEERS

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  • March 28, 2024
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  • 2023/2024
  • Class notes
  • Apm3715 assignment 1 solutions 2024 unisa
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,
, QUESTION 1

(a) Actual length = 14.5 meters

True length = 14.7 meters



Absolute error = 14.7 – 14.5 = 0.2

Relative error = (x0-x)/x = (Δx)/x = 0..5 = 0.01379




(b) 5.6789 = 5.679 (rounded off to 3 decimal places)



Absolute Error = 5.679 – 5.6789 = 0.0001

Relative error = (x0-x)/x = (Δx)/x = 0.0001/5.6789 = 1/56789 = 0.00001



5.6789 = 5.67 (truncated to 2 decimal places)

Absolute error = 5.6789 – 5.67 = 0.0089

Relative error = (x0-x)/x = (Δx)/x = 0.0089/5.67 = = 0.00156

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