Exam (elaborations)
Solution Manual For Power System Analysis and Design 7th Edition by J. Duncan Glover, Mulukutla S. Sarma, Thomas Overbye, Adam Birchfield
Institution
Solution Manual
Solution Manual For Power System Analysis and Design 7th Edition by J. Duncan Glover, Mulukutla S. Sarma, Thomas Overbye, Adam Birchfield
[Show more]
Preview 4 out of 402 pages
Uploaded on
April 30, 2024
Number of pages
402
Written in
2023/2024
Type
Exam (elaborations)
Contains
Questions & answers
Book Title: Power System Analysis and Design
Author(s): J. Duncan Glover, Mulukutla S. Sarma, Thomas Overbye, Adam Birchfield
Edition: 2022
ISBN: 9780357676394
Edition: Unknown
Institution
Solution Manual
Course
Solution Manual
By: mike_russo3 • 1 month ago
By: sorenheb • 2 months ago
R325,42
100% satisfaction guarantee
Immediately available after payment
Both online and in PDF
No strings attached
AN INSTRUCTOR’S SOLUT IONS MANUAL TO ACCOMPANY POWER SYST EM ANALYSIS AND DESIGN SEVENTH EDITION J. DUNCAN GLOVER THOMAS J. OVERBYE MULUKUT LA S. SARMA Adam B. Birchfield Contents Chapter 2........................................ ................................................... ................................. . 1 Chapter 3........................................ ................................................... ............................... . 24 Chapter 4........................................ ................................................... ............................... . 63 Chapter 5........................................ ................................................... ............................... . 85 Chapter 6........................................ ................................................... ............................. . 125 Chapter 7........................................ ................................................... ............................. . 160 Chapter 8........................................ ................................................... ............................. . 166 Chapter 9........................................ ................................................... ............................. .185 Chapter 10....................................... ................................................... ............................ . 219 Chapter 11....................................... ................................................... ............................ . 293 Chapter 12....................................... ................................................... ............................ . 314 Chapter 13....................................... ................................................... ............................ . 333 Chapter 14....................................... ................................................... ............................ . 346 Chapter 15....................................... ................................................... ............................ . 369 1 © 20 23 Cengage Learning®. May not be scanned, copied, or duplicated, or posted to a publicly accessible website, in whole or in part. Chapter 2 Fundamentals 2.1 (a) 𝐴̅1=9∠30°=9[𝑐𝑜𝑠 30°+𝑗 𝑠𝑖𝑛 30°]=7.8+𝑗4.5 (b) 𝐴̄2=4+𝑗5=√16+25 ∠𝑡𝑎𝑛−15
4=6.40∠128.66°=6.40𝑒𝑗128.66° (c) 𝐴̅3=(7.8+𝑗4.5)+(−4+𝑗5)=(11.8+𝑗9.5)=15.15∠38.8° (d) 𝐴4̅̅̅=(9∠30°)(6.4∠51.34°)=57.6∠81.34°=8.673+𝑗56.9 (e) 𝐴5̅̅̅=9∠30°
6.4∠−52.34°=1.41∠81.34°=1.41𝑒𝑗81.34° 2.2 (a) 𝐼̄=500∠−30°=433.01−𝑗250 (b) 𝑖(𝑡)=4𝑠𝑖𝑛(𝜔𝑡+15°)=4𝑐𝑜𝑠(𝜔𝑡+15°−90°)=4cos(𝜔𝑡−75°) 𝐼̅=4
√2∠−75°=2.83∠−75°=0.73−𝑗2.73 (c) 𝐼̄=(5/√2)∠−15°+4∠−60°=(3.42−𝑗0.92)+(2−𝑗3.46) =5.42−𝑗4.38=6.964∠−38.94° 2.3 𝑉̅2=13
√2∠(−(125×10−6)(2𝜋60)) kV=9.19∠−2.7° kV 2.4 (a) ()( )()1
21
26 6 9010 0 10 7.5 90 A8 6 6 8
10 0 7.3 90 10 7.5 12.5 36.87 A
6 12.5 36.87 6 90 75 53.13 VjIjj
I I I j
V I j− − = = = − +−
= − = − − = + =
= − = − = − (b) 2 © 20 23 Cengage Learning®. May not be scanned, copied, or duplicated, or posted to a publicly accessible website, in whole or in part. 2.5 (a) () () ( ) 277 2 cos 30 391.7cos 30 Vt t t = + = + (b) 𝐼̅=𝑉̅
45=6.155∠30° A 𝑖(𝑡)=8.7 cos (𝜔𝑡+30°) A (c) ()()
()( )
()()32 60 10 10 3.771 90
277 30 3.771 90 73.46 60 A
( ) 73.46 2 cos 60 103.9cos 60 AZ j L j
I V Z
i t t t
−= = =
= = = −
= − = − (d) ()()
() ()25
277 30 25 90 11.08 120 A
( ) 11.08 2 cos 120 15.67cos 120 AZj
I V Z
i t t t =−
= = − =
= + = + 2.6 (a) 𝑉̄=(75
√2)∠−15°=53.03∠−15°; does not appear in the answer. (b) 𝜐(𝑡)=50√2𝑐𝑜𝑠(𝜔𝑡+10°); with = 377, 𝜐(𝑡)=70.71𝑐𝑜𝑠(377𝑡+10°) (c) 𝐴̄=𝐴∠𝛼;𝐵̄=𝐵∠𝛽;𝐶̄=𝐴̄+𝐵̄ ( ) ( ) ( ) 2 Rejtc t a t b t Ce = + = The resultant has the same frequency . 2.7 (a) The circuit diagram is shown below: (b) 𝑍̶̄=3+𝑗8−𝑗4=3+𝑗4=5∠53.1° 𝛺 (c) ()() 100 0 5 53.1 20 53.1 AI= = − The current lags the source voltage by 53.1 Power Factor cos53.1 0.6 Lagging = =