Exam (elaborations)
MIP1501 ASSIGNMENT 03 DETAILED ANSWERS DUE: 22 JULY 2024 UNIQUE NO: (792287 )
- Course
- MIP1501
- Institution
- University Of South Africa (Unisa)
MIP1501 ASSIGNMENT 03 DETAILED ANSWERS DUE: 22 JULY 2024 UNIQUE NO: (792287 )
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By: nkwanagloria95 • 4 months ago
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,QUESTION 11.1. Solve and explain each step to grade 6 mathematics learners the
following multiplication and division calculations involving fractions.
ANSWER:
𝟖 𝟔
1.1.1 𝟔 ÷
𝟒 𝟏𝟐
𝟖
Step 1: Firstly, let’s solve or simplify 6
𝟒
First we multiply denominator(4) by whole number(6) which is
24
Then 24 will be added to numerator(8): 24 + 8 = 32
𝟑𝟐
Then will be =8
𝟒
𝟔
Step 2: Simplify:
𝟏𝟐
𝟔
Can be simplified by dividing the numerator and the
𝟏𝟐
denominator by their greatest common divisor (GCD), which is
6.
𝟔÷𝟔 𝟏
=
𝟏𝟐÷𝟔 𝟐
Step 3: Rewrite the division as multiplication by the reciprocal.
𝟏
Dividing by is the same as multiplying by its reciprocal, which
𝟐
is 2.
𝟏
So, 8 ÷ = 8 * 2
𝟐
, Step 4: Multiply.
8×2=16
𝟑𝟐 𝟔
So, ÷ = 16
𝟒 𝟏𝟐
𝟕 𝟒
1.1.2 x
𝟏𝟒 𝟏𝟖
𝟕
Step 1: Let’s simplify
𝟏𝟒
This can be simplified by dividing the numerator and the
denominator by their GCD, which is 7
𝟕 ÷ 𝟕 𝟏
=
𝟏𝟒 ÷ 𝟕 𝟐
𝟒
Step 2: simplify
𝟏𝟖
𝟒
can be simplified by dividing the numerator and the
𝟏𝟖
denominator by their GCD, which is 2
𝟒 ÷ 𝟐 𝟐
=
𝟏𝟖 ÷ 𝟐 𝟗
Step 3: Multiply the simplified fractions.
𝟏 𝟐 𝟏 𝐱 𝟐 𝟐
𝐱 = =
𝟐 𝟗 𝟐 𝐱 𝟗 𝟏𝟖
So then the final answer is:
𝟕 𝟒 𝟏
x =
𝟏𝟒 𝟏𝟒 𝟗
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