Exam (elaborations)
OPM1501 Assignment 3 (COMPLETE ANSWERS) 2024 (839387) - DUE 8 July 2024
- Course
- OPM1501
- Institution
- University Of South Africa
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OPM1501Assignment 3
(COMPLETE
ANSWERS)
2024 (839387) -
DUE 8 July 2024
CONTACT: biwottcornelius@gmail.com
Question 1 1.1. Complete the following function machines so that the inputs
give the correct outputs: a) 32 224 (3) b) 1080 − 960 (3) c) 525 25 (3) d) 510
, 270 (3) (12) 1.2. If you were asked to complete the following number line by
filling in the missing numbers, explain why it would not be possible to do so:
19 31 42 (4) 1.3. Provide two ways you can use to teach the students how to
generate the rule for each of the following: a) 32 224 (3) ….. − ….. …. ..
…. ….. b) 1080 − 960 (3) c) 525 25 (3) d) 510 270 (3) (12) 1.4. Fill out the
table below to show how many matches you would need for each diagram
number: (5) a) Write the rule for this pattern. (2) b) What formula could you
use for this pattern? (2) c) How many matchsticks would diagram number 37
have? (3) (12) [40]
Let's break down each part of Question 1 step by step:
1.1. Complete the function machines:
a) For 32 → 224
The rule here appears to be multiplying 32 by 7.
Calculation: 32×7=22432 \times 7 = 22432×7=224
b) For 1080 − 960
This simplifies to 1080−960=1201080 - 960 = 1201080−960=120.
c) For 525 → 25
The rule is dividing 525 by 21.
Calculation: 525÷21=25525 \div 21 = 25525÷21=25
d) For 510 → 270
This involves subtracting 240 from 510.
Calculation: 510−240=270510 - 240 = 270510−240=270
1.2. Completing the number line (19 31 42):
To determine why it's not possible to complete this number line, we observe the differences
between consecutive numbers:
Difference from 19 to 31: 31−19=1231 - 19 = 1231−19=12
Difference from 31 to 42: 42−31=1142 - 31 = 1142−31=11
Since the differences are not consistent (12 and 11), there is no simple arithmetic sequence that
fits all the given numbers. Therefore, we cannot extend the sequence using a single arithmetic
rule.
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