Exam (elaborations)
MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024
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- MIP1501
- Institution
- University Of South Africa
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MIP1501Assignment 3
(COMPLETE
ANSWERS)
2024 (792287) -
DUE 22 July
2024
CONTACT: biwottcornelius@gmail.com
, Question 1 (26) 1.1. Solve and explain each step to grade 6 mathematics
learners the following multiplication and division calculations involving
fractions. 1.1.1. 684÷ 612 (6) 1.1.2. 714× 418 (4) 1.1.3. 316× 624 (6) 1.1.4.
817÷ 124 (4) 1.2. Modelling refers to the idea that learners build in their minds
and play out with objects or in picture form on paper sometimes to solve
problems. Give and explain at least three benefits that you may achieve in
your primary mathematics class by employing modelling. (6)
Sure, let's go through each part step by step.
1.1.1. 684 ÷ 612
To solve 684612\frac{684}{612}612684:
1. Simplify the Fraction (if possible): Check if the fraction can be simplified by finding
the greatest common divisor (GCD) of 684 and 612.
o GCD of 684 and 612 is 12 (divide both numerator and denominator by 12).
684612=684÷12612÷12=5751\frac{684}{612} = \frac{684 ÷ 12}{612 ÷ 12} = \frac{57}
{51}612684=612÷12684÷12=5157.
2. Check for Further Simplification: GCD of 57 and 51 is 3 (divide both by 3).
5751=1917\frac{57}{51} = \frac{19}{17}5157=1719.
So, 684612=1917\frac{684}{612} = \frac{19}{17}612684=1719.
1.1.2. 714 × 418
To solve 714×418714 \times 418714×418:
1. Multiply the Numbers:
714×418=298,452714 \times 418 = 298,452714×418=298,452.
So, 714×418=298,452714 \times 418 = 298,452714×418=298,452.
1.1.3. 316 × 624
To solve 316×624316 \times 624316×624:
1. Multiply the Numbers:
316×624=197,184316 \times 624 = 197,184316×624=197,184.
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