Exam (elaborations)
MIP1501 Assignment 3 2024 (792287) - DUE 22 July 2024
- Course
- MIP1501 (MIP1501)
- Institution
- University Of South Africa (Unisa)
MIP1501 Assignment 3 2024 (792287) QUESTIONS AND ANSWERS
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MIP1501 Assignment 32024 (792287) - DUE
22 July 2024
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, MIP1501 Assignment 3 2024 (792287) - DUE 22 July 2024
Question 1 (26)
1.1. Solve and explain each step to grade 6 mathematics learners the following multiplication and division
calculations involving fractions. 1.1.1. 684÷ 612 (6)
1.1.2. 714× 418 (4)
1.1.3. 316× 624 (6)
1.1.4. 817÷ 124 (4)
1.2. Modelling refers to the idea that learners build in their minds and play out with objects or in picture
form on paper sometimes to solve problems. Give and explain at least three benefits that you may achieve
in your primary mathematics class by employing modelling. (6)
1.1. Calculations
1.1.1. 684 ÷ 612
To solve this division problem, we can simplify the fraction 684612\frac{684}{612}612684.
1. Find the greatest common divisor (GCD) of 684 and 612:
o The factors of 684 are: 1, 2, 3, 4, 6, 12, 19, 36, 57, 76, 114, 171, 228, 342, 684
o The factors of 612 are: 1, 2, 3, 4, 6, 12, 17, 18, 34, 51, 102, 153, 204, 306, 612
o The common factors are: 1, 2, 3, 4, 6, 12
o The greatest common divisor is 12.
2. Simplify the fraction:
684÷12612÷12=5751\frac{684 \div 12}{612 \div 12} = \frac{57}{51}612÷12684÷12=5157
3. Simplify further by dividing by their GCD (3):
57÷351÷3=1917\frac{57 \div 3}{51 \div 3} = \frac{19}{17}51÷357÷3=1719
4. Final Answer:
684612=1917\frac{684}{612} = \frac{19}{17}612684=1719
1.1.2. 714 × 418
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