Ace your further studies physics exam with my concise and clear Topic 5 charged particle notes notes. These notes cover electrical and magnetic fields, how charged particles behave in them as well as applications in real life and include practice questions and answers. Designed to save you time and...
T5 charged particles in electric and magnetic fields
41 Electric fields
Electric field Strength and Electric field lines
same as as in core
Uniform electric field
Fieldbetween parallel plate
Created by connecting to plates to obtain a potential difference
+ Side of plate is attached to
+ side batters (long SideI
Vice verso for -
Potential difference for
parallel plates
Work to I c change from the the lower potential
done of
plate with to
+
more the one
with higher potential
work
v = total charge
Equations
E = /from corel
Always Valid
E =
Valid for parallel plates
V= Potential difference d =
distance from plates
Equate them
F =
E and F constant everywhere between plates except at
edge
charged particles in uniform electric field
Particles attracted to plate of
opposite charge
Facing on
particle is vertical
Horizontal v is constant (ax =
0
Feles field acts on
particle
Ey also acts
Neutral particles
Fy is negligible due to small mass
undefletched
Equations
#net =
ma F =
ma =
g
ad
V
-
m
charge to mass Natio
Used to calculate mass/acceleration
Work energy and potential difference
Work energy thereom is used
Whet AE =
,
When no other forces appl
Combine differents
~ potential and work
energy
V= W net = Ei
: VQ =
W =
AEK
As
particle moves from 'plate to another Ep DER
Negative particle
Spontaneously mores from -
to +
plate
Electrical Ep DEx as is moves
Work is done by electric field
Non-spontaneously more from +
to-plate
External force must do work
, E=
3500
=
(2 5+,
,
%" ~
- "
14 104 V -
sin)
=
+ m to
place
.
- -v
v =
v
#B
-
v =
3500
=
+p
W =
5
,
607 + ,0 65
Whet = Ei
E = 5 [( , +")v2 Em()
607 + 1 6 =
-
-
6 ,
=
6 + 102 01
v =
3 , 51 +,
V +
100
towors
=
O
m
place
.
Some Force and work is applied , due to increase in mass ,
increase
in finid U
F = 19
Different
-
direction
-
4)
=
(400/1 ,
602 + 10
-
0 825
,
X
-
=
2, 5+ 10-N founds o plata
W constant a)
uniformly increasing
t
A
-
negitive
=
~
B: negitive
slightly
C :
Slightly positive
~
D =
Positive
Electric field and Malkin's experiment
Aim : To determine charge of e
Basic idea
charge oil
droplets due to friction as oil is sprayed through a nozzle
Balance droplet between parelle) plates
Hanging or constant motio
To be able to balance , droplet must repel from bottom plate
Felectrostatic
g
Eg
Eg Feles
E
=
E
=
my
=
L
Eg
my = q
mgd
: . v
q
=
Since volume was known Hr" for Sphere) and moss/p E =
density
could calculate charge
Results
All multiples of 1
,
6710 (
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through EFT, credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying this summary from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller ethansharfman. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy this summary for R75,00. You're not tied to anything after your purchase.
