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MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024
MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024
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, MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) -DUE 22 July 2024 ;100% TRUSTED workings, explanations and
solutions.
Question 1 (26) 1.1. Solve and explain each step to grade 6 mathematics
learners the following multiplication and division calculations involving
fractions. 1.1.1. 684÷ 612 (6) 1.1.2. 714× 418 (4) 1.1.3. 316× 624 (6) 1.1.4.
817÷ 124 (4) 1.2. Modelling refers to the idea that learners build in their minds
and play out with objects or in picture form on paper sometimes to solve
problems. Give and explain at least three benefits that you may achieve in
your primary mathematics class by employing modelling. (6)
Question 1.1: Solve and explain each step for the following calculations involving
fractions to grade 6 mathematics learners.
1.1.1. 684 ÷ 612
To solve this division problem, we can simplify the fraction 684612\
frac{684}{612}612684.
1. Find the greatest common divisor (GCD) of 684 and 612:
o Factors of 684: 1, 2, 3, 4, 6, 12, 19, 36, 57, 114, 171, 342, 684
o Factors of 612: 1, 2, 3, 4, 6, 12, 17, 34, 51, 102, 153, 204,
306, 612
o The GCD of 684 and 612 is 12.
2. Divide both the numerator and the denominator by the GCD (12):
o 684÷12612÷12=5751\frac{684 ÷ 12}{612 ÷ 12} = \frac{57}
{51}612÷12684÷12=5157
3. Simplify the fraction:
o Find the GCD of 57 and 51, which is 3.
o 57÷351÷3=1917\frac{57 ÷ 3}{51 ÷ 3} = \frac{19}
{17}51÷357÷3=1719
So, 684÷612=1917684 ÷ 612 = \frac{19}{17}684÷612=1719 or 1.117
(approximately).
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