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DSC1630 Assignment 1 (COMPLETE ANSWERS) Semester 2 2024 (234521)- DUE 8 August 2024 ; 100% TRUSTED Complete, trusted solutions and explanations R46,71   Add to cart

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DSC1630 Assignment 1 (COMPLETE ANSWERS) Semester 2 2024 (234521)- DUE 8 August 2024 ; 100% TRUSTED Complete, trusted solutions and explanations

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DSC1630 Assignment 1 (COMPLETE ANSWERS) Semester 2 2024 (234521)- DUE 8 August 2024 ; 100% TRUSTED Complete, trusted solutions and explanations

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Assignment 1
DUE 8
August 2024
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 Introduction to Financial Mathematics

DSC1630 Assignment 1 (COMPLETE ANSWERS) Semester 2 2024
(234521)- DUE 8 August 2024 ; 100% TRUSTED Complete, trusted solutions
and explanations



Question 1 Not yet answered Marked out of 1.00 QUIZ You have invested R1
500 in an account earning 6,57% simple interest. The balance in the account
16 months later is a. R1 636,94. b. R2 814,00. c. R1 631,40. d. R1 644,02.
Clear my choice DSC1630-24-S2  Welcome Message  Assessment 1
Figuring out the issue:

• Chief sum (P) = R1 500

• Financing cost (R) = 6.57% each year

• Time (T) = 16 months

Recipe for Straightforward Interest:

• Basic Interest (SI) = (P * R * T)/100

Computations:

1. Convert months to years: 16 months = 16/12 = 4/3 years

2. Calculate Straightforward Interest: SI = (1500 * 6.57 * 4/3)/100 =
R131.40

3. Calculate the equilibrium: Equilibrium = Head + Straightforward
Interest = 1500 + 131.40 = R1631.40

Reply:

• The equilibrium in the record 16 months after the fact is R1 631.40.

Subsequently, the right choice is c. R1 631.40.

, Question 2 Not yet answered Marked out of 1.00 QUIZ If money is worth 12%
per annum compounded monthly, how long will it take the principal P
tobecome four times the original value? a. 11,61 years b. 7,27 years c. 69,66
years d. 139,32 years Clear my choice DSC1630-24-S2  Welcome Message
 Assessment 1

To figure out measure of opportunity its expectation for a hypothesis to
turn into different times its one of a kind worth with gather interest, we
use oneself duplicating profits recipe:

A=P(1+rn)ntA = P(1 + \frac{r}{n})^{nt}A=P(1+nr)nt

Where:

• AAA is the last total

• PPP is the head (starting aggregate)

• rrr is the yearly credit cost (as a decimal)

• nnn is the times the interest is amassed every year

• ttt is the amount of years

Given:

• A=4PA = 4PA=4P (considering the way that the aggregate turns
into various times the head)

• r=12%=0.12r = 12\% = 0.12r=12%=0.12

• n=12n = 12n=12 (escalated month to month)

We truly need to find ttt.

Substitute the characteristics into the recipe:

4P=P(1+0.1212)12t4P = P\left(1 + \frac{0.12}{12}\
right)^{12t}4P=P(1+120.12)12t

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