Exam (elaborations)
MIP1502 ASSIGNMENT 4 ANSWERS 2024
- Course
- MIP1502 (MIP1502)
- Institution
- University Of South Africa (Unisa)
MIP1502 ASSIGNMENT 4 ANSWERS 2024
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2024MIP1502 ASSIGNMENT 4
ANSWERS 2024
MIP1502
ASSIGNMENT 4
ANSWERS 2024
,MIP1502
Assignment 4: Compulsory
Contributes 25% to the final pass mark
Unique number: 397869
Due date: 16 August 2024
Question 1
1.1 A tiling configuration is made by organizing dull and red squares, as shown
below:\
1.1.1 Complete the table underneath for tile numbers 5 and 6.
complete the table underneath for tile numbers 5 and 6 (6 core interests):
To find the missing characteristics for tile numbers 5 and 6, could we first truly check
out at the models in the given data:
- The amount of red squares \( R \) follows a numerical progression with a run of the
mill differentiation of 2:
- 4, 6, 8, 10 ...
, - It emits an impression of being \( R = 2n + 2 \).
- The amount of dim squares \( B \):
- 5, 10, 17, 26...
- The differentiation progresses as follows:
- Contrast: 5, 7, 9 (which increases by 2 each time)
- Consequently, it appears to follow a quadratic gathering. We can convey this as a
polynomial condition.
To resolve the total squares \( S \) for tile numbers 5 and 6:
- The total number of squares is apparently the square of the tile length \( l \).
- The relationship \( S = l^2 \); where \( l \) is 3 (for tile number 1), so without a doubt,
each tile length is \( n + 2 \).
Tolerating tile number \( n \):
- For \( n = 5 \), \( l \) would move toward 5, and for tile \( n = 6 \), \( l \) would ascend
to 6. In this manner, squares will be:
- \( 5^2 = 25 \)
- \( 6^2 = 36 \)
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