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MSE2183 ASSIGNMENT 03 Complete Solutions UNISA 2024 GEOMETRY Due date 02 September 2024 Mathematics 218 for BED R150,00   Add to cart

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MSE2183 ASSIGNMENT 03 Complete Solutions UNISA 2024 GEOMETRY Due date 02 September 2024 Mathematics 218 for BED

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MSE2183 ASSIGNMENT 03 Complete Solutions UNISA 2024 GEOMETRY Due date 02 September 2024 Mathematics 218 for BED

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  • August 29, 2024
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MSE2183
ASSIGNMENT 3
FULL SOLUTIONS
Due date: 02 September 2024
Unique Number: 693219
Complete Solutions
Geometry

UNISA
2024

,Question 1

Name and Surname:
Student Number:
My posts in Forum 4




Other students’
responses /
comments on




My comments on
other students’ posts
NB: Discuss fully.
(A zero mark will be
awarded for
responses/comments
like
‘I fully agree with your
statement’; ‘Good
work’; ‘indeed’ and
more other
superficial/insignifica
nt
responses/comments)

,SOLUTION

Question 2

2.1 Perimeter 1 = 2L + 2B = 2(a) + 2(b) = 2a + 2b

Perimeter 2 = 2(2a) + 2(b/2) = 4a + b

Now , if 4a + b = 2a + 2b

2a – b = 0

b = 2a

Hence the two rectangles have the same perimeter whenever b = 2a , where a and b

are real numbers.

, Area of rectangle 1 = Length x Breadth

=axb

= ab

Area of rectangle 2 = Length x Breadth

= 2a x (b/2)

= ab

Hence the two rectangles have the same area for all real values of a and b.

2.2 Perimeter of a dodecagon = 12S

= 12( 7cm)

= 84 cm

2.3 Perimeter of an equilateral Octagon = 8S

42 = 8S

S = 42/8

S = 21/4

S = 5.25 cm

2.4




Perimeter of figure = 2(x -3) + 2(x + 8) + 16

94 = 2x – 6 + 2x + 16 + 16

94 -26 = 4x

68 = 4x

x = 68/4

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