21 questions were answered correctly.
2 questions were answered incorrectly.
1
●
The table below shows the results of a
customer satisfaction survey at a particular
restaurant broken down by males and females.
Male Female
Extremely Satisfied 25 7
Satisfied 21 13
Neutral 13 16
Dissatisfied 9 14
Extremely Dissatisfied 2 5
Assuming all 5 choices are equally likely, select
the observed and expected frequency for male
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:
, customers that are dissatisfied.
Observed: 9
#
Expected: 14
Observed: 9
●
Expected: 25
Observed: 9
●
Expected: 12.5
Observed: 14
●
Expected: 9
RATIONALE
If we simply go to the chart then we can
directly see the observed frequency for male
customers who are dissatisfied is 9.
To find the expected frequency, we need to
find the number of
occurrences if the null hypothesis is true,
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:
, which in this case, was that the five options
are equally likely, or if the five options were all
evenly distributed.
First, add up all the options in the Male
column:
If each of these five options were evenly
distributed among the 70 males, we would
need to divide the total evenly between the
five options:
This means we would expect 14 men to be
extremely satisfied, satisfied, neutral,
dissatisfied, and extremely dissatisfied.
CONCEPT
→ Chi-Square Statistic
Report an issue with this question
2
●
Which of the following assumptions for a two-
way ANOVA is FALSE?
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:
, The groups must
have the same
●
sample size.
The samples must be
# dependent.
The variances of the
populations must be
●
equal.
The sample
populations must be
normally or
●
approximately
normally distributed.
RATIONALE
Inside of the one-way ANOVA we assume that
we take an independent and identically
distributed sample. So we don't assume
dependence.
CONCEPT
→ One-Way ANOVA/Two-Way ANOVA
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:
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