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PHY1506 EXAM PACK 2025 {DETAILED QUESTIONS AND ANSWERS } R52,04
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PHY1506 EXAM PACK 2025 {DETAILED QUESTIONS AND ANSWERS }

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PHY1506 EXAM PACK 2025 {DETAILED QUESTIONS AND ANSWERS }

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  • November 10, 2024
  • 71
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
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Chapter 1
Macroscopic description of matter

1.1 State of the matter
There are three common states of the matter
1. Solid
- Incompressible
- particles-like atoms connected by molecular
bonds - etc.

2. Liquid:
- Formed by loosely-bound together molecules.
- Nearly incompressible.
- Flows and deforms to fit the shape of the
container.
- etc.
3. Gas:
- Highly compressible - Large space between
molecules - etc.

1


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2 CHAPTER 1. MACROSCOPIC DESCRIPTION OF MATTER

1.2 State variables
State variables are parameters used to
characterize or describe a macroscopic system. A
system is said to be in thermal equilibrium if the
state variables are constant, i.e., not changing.

1.3 Atoms and moles
The mass of a system is related to its number of
atoms or molecules (we represent this number by
N). The number of atoms or molecules per unit
of volume is called number density, defined by
the ratio N/V , where V is the volume of the
system. Notice that the number density is the
same whether one considers the whole system or
a portion of it. This means that the value of the
ratio N/V is constant.

1.3.1Atomic mass and atomic mass number
(a) Atomic mass Since the atom is composed of
protons and neutrons, the atomic mass number
represents the sum of protons and neutron of
the atom, and is given by
A = Nn + Np,
where
A: atomic mass number
Nn: number of neutrons
Np: number of protons
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Example:
1
H: A = 1
4
He: A = 4
12
C: A = 12.
(b) Atomic mass (unit “u”)
The atomic mass is obtained by considering
the mass of Carbon-12 (12C) to be exactly 12u.
This means that m(12C) = 12u. For example, an
experimental study of the hydrogen atom
showed that the ration m(1H)/m(12C) =
1.0078/12. This means that the atomic mass of
hydrogen is 1.0078u. In this study guide, we
will loosely define the atomic mass of a
chemical element as its mass number with the
unit “u”. For example, the atomic mass of
Helium will be m(4He) = 4u, m(20Ne) = 20u,
etc.




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