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BNU1501 Exam May June 2019 Questions and Solutions

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BNU1501 Exam May June 2019 Questions and Solutions with workings.

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  • October 2, 2020
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Basic Numeracy
BNU1501
Department of Decision Sciences
Exam May/June 2019




Question 1

Simplify the following expression as far as possible:

6𝑎2 − 9𝑎𝑏 + 2𝑏 2 − 3(𝑏𝑎 − 𝑏 2 )
2 2 2 2
[1] 6𝑎 − 𝑏 + 12𝑎 𝑏
[2] 6𝑎2 − 12𝑎𝑏 + 5𝑏 2
[3] 6𝑎2 + 3𝑏 2 − 12𝑏𝑎
[4] 6𝑎2 − 12𝑎𝑏 − 𝑏 2
Answer:
6𝑎2 − 9𝑎𝑏 + 2𝑏 2 − 3(𝑏𝑎 − 𝑏 2 )
Reorder the terms:
6𝑎2 − 9𝑎𝑏 + 2𝑏 2 − 3(𝑎𝑏 − 3𝑏 2 )
Distribute 3 through the parentheses:
6𝑎2 − 9𝑎𝑏 + 2𝑏 2− − 3𝑎𝑏 + 3𝑏 2
Collect like terms:
6𝑎2 − 12𝑎𝑏 + 2𝑏 2 + 3𝑏 2
6𝑎2 − 12𝑎𝑏 + 5𝑏 2

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