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Summary Grade 12 IEB Physical Sciences - Work, Power and Energy Notes (Physics Section C - 5A, 5C, 5D, 5E) R50,00   Add to cart

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Summary Grade 12 IEB Physical Sciences - Work, Power and Energy Notes (Physics Section C - 5A, 5C, 5D, 5E)

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Covers the various sections relating to Work, Energy and Power. Includes notes from the textbook, as well as additional class, video and research information, diagrams and practice questions. Applicable to all IEB Grade 12s. Written by a 95% < student.

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  • December 14, 2020
  • 10
  • 2020/2021
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By: gerritcleroux • 3 year ago

Spelling and unwilling to fix it before final exams in November to where I do not need the notes for afterwards.

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KirstenBarbour
Work, Energy, Power
Work “done by a force”
= The product of the displacement and the component of force parallel to the displacement
(scalar quantity)


Must be movement.
Up/down or sideways.
Symbol: W
Unit = J
Can be negative e.g. Frictional force

W = F. ∆x . cos θ
F in newtons. (Always positive)
∆x in metres. (Always positive)
cos θ in degrees. (Determines the direction)



F
θ
∆x
θ is the angle between the force and the displacement.

F W=+
∆x


F
∆x W = +


F
W=0 ∆x


F
W=- ∆x



Any force that does work on an object that increases the kinetic energy of an object
= positive work
e.g. engine force

Any force that does work on an object that decreases the kinetic energy of an object
= negative work
e.g. braking force

, Work example
2kg is pulled 12m horizontally by a 10N force. There is a notable 3N frictional force.

FN
Fnet = 7N
∆x
F = 10N
Ff = 3N


Fg


WFg = Fg . ∆x . cosθ or Wnet = Fnet . ∆x . cosθ
.. = Fg . ∆x . cos(90°) = 7 x 12 x cos(0)
.. = 0 J = 7 x 12 x 1
.. = 84 J

WFN = FN. ∆x . cosθ
.. = FN . ∆x . cos(90°)
.. = 19.6 x 12 x 0
.. = 0 J

WF = F. ∆x . cosθ
.. = F. ∆x . cos(0°)
.. = 10 x 12 x 1
.. = 120 J

WFf = Ff. ∆x . cosθ
.. = F. ∆x . cos(180°)
.. = 3 x 12 x -1
.. = -36 J

Wnet = 0 + 0 + 120 + (-36)
.. = 84 J

Or

∆Ek = Ekf – Eki

Vf = ??
Vi = 4
Δx = 12
a= Fnet = ma
.. 7=2xa
.. .. a = 3.5

Vf2 = Vi2 + 2aΔx
… = (4)2 + 2(3.5)(12)
.. = 100
Vf = 10 m/s

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