Differential Equations APM2611 (APM2611)
University of South Africa
All 4 results
Sort by
-
APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024
- Exam (elaborations) • 23 pages • 2024
-
- R49,20
- 2x sold
- + learn more
-
APM2611 Assignment 2 (COMPLETE ANSWERS) 2024 - DUE 19 June 2024
- Exam (elaborations) • 23 pages • 2024 Popular
-
- R49,20
- 1x sold
- + learn more
APM2611 Assignment 2 (COMPLETE ANSWERS) 2024 - DUE 19 June 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... 
 
ASSIGNMENT 02 
Due date: Wednesday, 19 June 2024 
- 
ONLY FOR YEAR MODULE 
Series solutions, Laplace transforms and Fourier series, solving PDE’s by separation of 
variables. 
Answer all the questions. Show all your own and personalized workings, you get ZERO 
to a question if we see that ...
-
APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024
- Exam (elaborations) • 20 pages • 2024
-
- R45,39
- + learn more
APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024 
Question 1 
1. Find the radius and interval of convergence of the following series: ( 
i) ∞X n=1 100n n! (x + 7) n 
(ii) ∞X k=1 (−1) k 10k (x − 5) k 
2. Rewrite the expression below as a single power series: ∞X n=2 n(n − 
1)cn x n + 2 ∞X n=2 n(n − 1)cn x n−2 + ∞X n=1 ncn x n . 
Question 2 
1. Verify by direct substitution that the given power series is a particular 
solution of the DE (x + 1)y 00+ y 0 = 0 ; y ...
-
APM2611 Assignment 4 (COMPLETE ANSWERS) 2024 - DUE 25 September 2024
- Exam (elaborations) • 22 pages • 2024
-
- R49,20
- 1x sold
- + learn more
APM2611 Assignment 4 (COMPLETE ANSWERS) 2024 - DUE 25 September 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... 
 
Question 1 
1. Find the radius and interval of convergence of the following series: 
∞X 
n=1 
(−1) n−1 x2n−1 
(2n − 1)! 
2. Rewrite the expression below as a single power series: 
∞X 
n=2 
cn+1 x 
n−2 − 
∞X 
n=1 
4cn x 
n−1 . 
3. Use the power series method to solve ...
Want to regain your expenses?
How much did you already spend on Stuvia? Imagine there are plenty more of you out there paying for study notes, but this time YOU are the seller. Ka-ching! Discover all about earning on Stuvia