Qmi1500 assignment 2 2022 - Study guides, Study notes & Summaries
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QMI1500 Assignment 1 semester 2 2022 .
- Exam (elaborations) • 24 pages • 2022
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QMI1500 Assignment 1 semester 2 
2022 . 
ANSWER 
((−49) ÷ 7 × 3(−8)) ÷ 4 + (6 × 3) − 21 ÷ 3) 
(−7 × 3(−8)) ÷ 4 + (6 × 3) − 21 ÷ 3) 
168 ÷ 4 + (6 × 3) − 21 ÷ 3 
42 + 18 − 21 ÷ 3 
42 + 18 − 7 
60 − 7 
53 (OPTION
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QMI1500-assignment-3-semester-2-2022.
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QMI1500-assignment-3-semester-2-2022. 
QUESTION 1 
PMT = 480 700 
N = 20 
I = 7.5% 
CMPT PV = 4 900 49
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QMI1500 ASSIGNMENT 3 SEMESTER 1 & 2 2022
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QMI1500 
 
ASSIGNMENT 3 SEMESTER 1 & 2 2022 UNIQUE NUMBER: 
 
PREVIEW OF QUESTION 1 
1.	4	Time value of money calculations PMT = 7440 
N = 10 x 4 = 40 I = 11/4 
 
CMPT FV = 530 235 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
	 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1. 4	Time value of money calculations 
PMT = 7440 
N = 10 x 4 = 40 I = 11/4 
 
CMPT FV = 
 
 
2. 3	PMT = 480 700 
N = 20 
I = 7.5 
 
CMPT PV = 
 
 
3. 3	FV = 330 284,00 
N = 4 x 12 = 48 I = 12.5/12 
 
CMPT PMT = 
 
 
 
 
 
 
 
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QMI1500 ASSIGNMENT 1 SEMESTER 2 - 2022 (708746)
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QMI1500 ASSIGNMENT 1 SEMESTER 2 - 2022 
 
UNIQUE NUMBER:
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QMI1500 | NEW Assignment Pack (1,2 and 3| 2022 | Semester 01
- Summary • 71 pages • 2022
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QMI1500 | NEW Assignment Pack (1,2 and 3| 2022
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QMI1500 Assignment 3 Semester 2 2022
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QMI1500 Assignment 3 Semester 2 2022 
QMI1500 Assignment 3 Semester 2 2022
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QMI1500 ASSIGNMENT 1 SOLUTIONS SEMESTER 2 2022
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QMI1500 ASSIGNMENT 1 SOLUTIONS SEMESTER 2 2022
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QMI1500 ASSIGNMENT 01SOLUTIONS, SEMESTER 2, 2022
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QMI1500 ASSIGNMENT 01SOLUTIONS, SEMESTER 2, 2022
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QMI1500 ASSIGNMENT 01 SEMESTER 01 - 2022
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QMI1500 ASSIGNMENT 01 SEMESTER 01 - 2022 
QUESTION 1 
 
Solving 
 
−7 − 3 × 2(−5) + 6 − 21 ÷ 3 
 
gives 
 
[1]	26. 
[2]	99. 
[3]	95. 
[4]	22. 
 
Simplifying the expression gives: 
 
FOLLOW THE BEMDAS ORDER OF OPERATIONS 
 
Brackets; Exponents; Multiplication & Division; Addition & Subtraction: 
 
−7 − 3 × 2 (−5) + 6 − 21 ÷ 3	 
	Multiply and divide (left to right): 3 × 2 ( −5) = -30 
	3 × 2 ( -5) 
	3 × 2 = 6 
	= 6( - 5) 
= −7 – ( -30) + 6 – 21 ÷ 3	 
	Apply rule:
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