Apm2611 assignment 1 2024 - Study guides, Study notes & Summaries
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APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024
- Exam (elaborations) • 23 pages • 2024
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APM2611 ASSIGNMENT 1 FULL SOLUTIONS UNISA 2024 ORDINARY DIFFERENTIAL EQUATIONS
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APM2611 ASSIGNMENT 1 FULL SOLUTIONS UNISA 2024 ORDINARY DIFFERENTIAL EQUATIONS
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APM2611 Assignment 2 2024 - DUE 19 June 2024
- Exam (elaborations) • 23 pages • 2024
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APM2611 Assignment 2 2024 - DUE 19 June 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... 
 
ASSIGNMENT 02 
Due date: Wednesday, 19 June 2024 
- 
ONLY FOR YEAR MODULE 
Series solutions, Laplace transforms and Fourier series, solving PDE’s by separation of 
variables. 
Answer all the questions. Show all your own and personalized workings, you get ZERO 
to a question if we see that you have copied som...
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APM2611 Assignment 2 (COMPLETE ANSWERS) 2024 - DUE 19 June 2024
- Exam (elaborations) • 23 pages • 2024
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APM2611 Assignment 2 (COMPLETE ANSWERS) 2024 - DUE 19 June 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... 
 
ASSIGNMENT 02 
Due date: Wednesday, 19 June 2024 
- 
ONLY FOR YEAR MODULE 
Series solutions, Laplace transforms and Fourier series, solving PDE’s by separation of 
variables. 
Answer all the questions. Show all your own and personalized workings, you get ZERO 
to a question if we see that ...
-
APM2611 Assignment 4 (COMPLETE ANSWERS) 2024 - DUE 25 September 2024
- Exam (elaborations) • 22 pages • 2024
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APM2611 Assignment 4 (COMPLETE ANSWERS) 2024 - DUE 25 September 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... 
 
Question 1 
1. Find the radius and interval of convergence of the following series: 
∞X 
n=1 
(−1) n−1 x2n−1 
(2n − 1)! 
2. Rewrite the expression below as a single power series: 
∞X 
n=2 
cn+1 x 
n−2 − 
∞X 
n=1 
4cn x 
n−1 . 
3. Use the power series method to solve ...
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APM2611 Assignment 1 (COMPLETE ANSWERS) 2024
- Exam (elaborations) • 22 pages • 2024
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APM2611 Assignment 1 (COMPLETE ANSWERS) 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)...........
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APM2611 Assignment 3 2024 - DUE 14 August 2024
- Exam (elaborations) • 23 pages • 2024
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APM2611 Assignment 3 2024 - DUE 14 August 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... 
 
Question 1 
1. Find the radius and interval of convergence of the following series: 
(i) 
∞X 
n=1 
100n 
n! 
(x + 7) n 
(ii) 
∞X 
k=1 
(−1) k 
10k 
(x − 5) k 
2. Rewrite the expression below as a single power series: 
∞X 
n=2 
n(n − 1)cn x 
n 
+ 2 
∞X 
n=2 
n(n − 1)cn x 
n−2 + 
∞X 
n=1 
n...
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APM2611 Assignment 4 2024 - DUE 25 September 2024
- Exam (elaborations) • 22 pages • 2024
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APM2611 Assignment 4 2024 - DUE 25 September 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... 
 
Question 1 
1. Find the radius and interval of convergence of the following series: 
∞X 
n=1 
(−1) n−1 x2n−1 
(2n − 1)! 
2. Rewrite the expression below as a single power series: 
∞X 
n=2 
cn+1 x 
n−2 − 
∞X 
n=1 
4cn x 
n−1 . 
3. Use the power series method to solve the initialvalue pr...
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APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024
- Exam (elaborations) • 20 pages • 2024
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- R46,62
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APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024 
Question 1 
1. Find the radius and interval of convergence of the following series: ( 
i) ∞X n=1 100n n! (x + 7) n 
(ii) ∞X k=1 (−1) k 10k (x − 5) k 
2. Rewrite the expression below as a single power series: ∞X n=2 n(n − 
1)cn x n + 2 ∞X n=2 n(n − 1)cn x n−2 + ∞X n=1 ncn x n . 
Question 2 
1. Verify by direct substitution that the given power series is a particular 
solution of the DE (x + 1)y 00+ y 0 = 0 ; y ...
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