Consider the system of linear equations, where the information regarding the system is
represented by the augmented matrix below:
k 1 1 0
E = [0 k − 1 0 | −2 ]
0 0 k2 − 1 k + 1
The system is inconsistent for:
a. k=0
b. k = 2 and k = −1
c. k=1
d. k = −1
SOLUTION
The system is already in REF. To determine the solutions, we look at the last row.
No solution Exactly one solution Infinitely many solutions
For the above system to be For the above system to be For the above system to have
inconsistent (no solution), the consistent (exactly one infinitely many solutions the last
last row must be of the form: solution), the last row must be row must be of the form:
of the form:
[0 0 0| ∗] [0 0 0| 0]
[0 0 ∗| ∗]
where * is any real number Thus, k2 − 1 = 0 and k + 1 = 0
except zero (0). where * are any real numbers ⇒ k = ±1 . Thus,
except zero (0). for the above system to have
Thus, k2 − 1 = 0 and k + 1 ≠ 0 infinitely many solutions
⇒ k = ±1 and k ≠ −1. Thus, Thus, k2 − 1 ≠ 0 and k + 1 ≠ 0 𝐤 = −𝟏.
for the above system to be ⇒ k ≠ ±1 . Thus,
inconsistent 𝐤 = 𝟏 for the above system to have
exactly one solution
𝐤 ∈ ℝ, except 𝐤 ± 𝟏.
Given two square matrices X and Y of the same size such that (X − Y)(Y + X) = X2 − Y2.
Which of the following statements is correct?
a. XY = O, where O is the zero matrix of the same dimension as X and Y.
b. X=Y
c. X and Y are inverses of each other
d. XY = YX
SOLUTION
(X − Y)(Y + X) = X2 − Y2 XY = YX in those special cases
where X and Y commute ∵ matrix
(X − Y)(Y + X) = X2 − Y2 multiplicand is not commutative
in general.
X. Y + X. X − Y. Y − Y. X = X2 − Y2
XY + X2 − Y2 − YX = X2 − Y2
X2 − Y2 + XY − YX = X2 − Y2
Now for the LHS to be equal to the RHS ⇒ XY = YX, hence XY −
YX = zero matrix.
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